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LenaWriter [7]
3 years ago
15

What is the equation in point slope form for the line that is parallel to y=-8x-12 that contains the point (-3,3)

Mathematics
1 answer:
belka [17]3 years ago
3 0

Answer:

The equation of a parallel line in point-slope form would be y - 3 = -8(x + 3)

Step-by-step explanation:

To find this, we must first note that the original slope is -8. Parallel lines have the same slope, so we know that the new line will also have the slope of -8.

Given this information, we can use the point and slope and put them into the base form of point-slope form.

y - y1 = m(x - x1)

y - 3 = -8(x - -3)

y - 3 = -8(x + 3)

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Answer: x = 1

Step-by-step explanation:

Simplifying

-4(-6x + 3) = 12

Reorder the terms:

-4(3 + -6x) = 12

(3 * -4 + -6x * -4) = 12

(-12 + 24x) = 12

Solving

-12 + 24x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 12 + 24x = 12 + 12

Combine like terms: -12 + 12 = 0

0 + 24x = 12 + 12

24x = 12 + 12

Combine like terms: 12 + 12 = 24

24x = 24

Divide each side by '24'.

x = 1

Simplifying

x = 1

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Step-by-step explanation:

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