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LenaWriter [7]
3 years ago
15

What is the equation in point slope form for the line that is parallel to y=-8x-12 that contains the point (-3,3)

Mathematics
1 answer:
belka [17]3 years ago
3 0

Answer:

The equation of a parallel line in point-slope form would be y - 3 = -8(x + 3)

Step-by-step explanation:

To find this, we must first note that the original slope is -8. Parallel lines have the same slope, so we know that the new line will also have the slope of -8.

Given this information, we can use the point and slope and put them into the base form of point-slope form.

y - y1 = m(x - x1)

y - 3 = -8(x - -3)

y - 3 = -8(x + 3)

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Answer:

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Step-by-step explanation:

When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.

The coefficient of the squared term is 1/36.

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Jim Debt was reviewing the total accounts receivable. This month he received $80,000 from Credit customers. This represented 40
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Answer:

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Step-by-step explanation:

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Its worth committing this mnemonic to memory, which helps to find the required trig ratio:

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