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3 years ago

What is the radius of a circle with an area of 113.04 cubic inches? Use 3.14 for pi.

Mathematics

1 answer:

frosja888 [35]3 years ago

6 0

Answer:

I am deeply sorry for the late answer

but the answer is The answer is

r ≈ 6

Step-by-step explanation:

The answer is r ≈ 6

A ≈ 113.04 cubic in.

this means that

d ≈ 12

and

C ≈ 37.69

Therefore

r ≈ 6

Hope this helped.

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There are 500 students in a high school senior class. Of these 500 students, 300 regularly wear a necklace to

andre [41]

Answer:

1. P(N) = 3/5

2. P(R) = 2/5

3. P(N and R) = 1/4

4. P(N or R) = 3/4

Step-by-step explanation:

1. Let's review the information given to us to answer the problem correctly:

Number of students in a high school senior class = 500

Number of students that regularly wear a necklace = 300

Number of students that regularly wear a ring = 200

Number of students that wear a necklace and a ring = 125

2. What is P(N), the probability that a senior wears a necklace?

Let's recall the formula of probability:

Probability = Number of favorable outcomes/Total of possible outcomes

Substituting with the real given values:

P(N) = 300/500 = 3/5 (Dividing by 100 numerator and denominator)

P(N) = 3/5

3. What is P(R), the probability that a senior wears a ring?

Substituting with the real given values:

P(R) = 200/500 = 2/5 (Dividing by 100 numerator and denominator)

P(R) = 2/5

4. What is P(N and R), the probability that a senior wears a necklace and a ring?

Substituting with the real given values:

P(N and R) = 125/500 = 1/4 (Dividing by 125 numerator and denominator)

P(N and R) = 1/4

5. What is P(N or R), the probability that a senior wears a necklace or a ring?

P(N or R) = P(N) + P(R) - P(N and R)

Substituting with the real given values:

P(N or R) = 3/5 + 2/5 - 1/4

P(N or R) = 5/5 - 1/4

P(N or R) = 1 - 1/4

P(N or R) = 3/4

5 0

3 years ago

A shipment of 40 fancy calculators contains 3 defective units. What is the probability if a college bookstore buys 20 calculator

JulsSmile [24]

Answer:

38.46%

Step-by-step explanation:

There are no names or marking that can make the calculator look different, so the order is not important. Then we should use a combination to solve this problem.

There are 40 calculators in one shipment, 37 of them good items and 3 of them are defect items. We need to choose 19 good calculators and 1 defect calculator. The number of ways to do that will be:

$\frac{37}{19}$ * $\frac{3}{1}$ = 37! $\frac{37!}{19!(37-19!)} * \frac{3!}{1!(3-1)!}$ = 53017895700