Answer:
5 i believe correct me if im wrong
Step-by-step explanation:
To work this problem out you would do it as if it were just a simple equation
7x-19<16 (you would first have to add 19 to both sides)
7x<35 (then you would divide by 7 to get the variable by itself)
x<5 ( you answer would then be 5)
Answer:
wait 3mm thats ow big my.........
Step-by-step explanation:
Answer: 2 1/2 miles
Step-by-step explanation:
To subtract fractions with different denominators (in this problem they are 10 and 5), you have to find the least common denominator or LCD (10). Then you have to multiply the numerator and the denominator of 4/5 by 2 to turn the denominator into the LCD (10).
1. So 2 4/5 turns into 2 8/10
2. Then subtract 2 8/10 from 5 3/10 to get the answer 2 1/2
![\bf ln\left( \sqrt[7]{e^4} \right)\implies log_e\left( e^{\frac{4}{7}} \right)\\\\ -----------------------------\\\\ log_{{ a}}{{ a}}^x\implies x=x\impliedby \textit{let's use this cancellation rule}\\\\ -----------------------------\\\\ log_e\left( e^{\frac{4}{7}} \right)\iff \cfrac{4}{7}](https://tex.z-dn.net/?f=%5Cbf%20ln%5Cleft%28%20%5Csqrt%5B7%5D%7Be%5E4%7D%20%5Cright%29%5Cimplies%20log_e%5Cleft%28%20e%5E%7B%5Cfrac%7B4%7D%7B7%7D%7D%20%5Cright%29%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Alog_%7B%7B%20%20a%7D%7D%7B%7B%20%20a%7D%7D%5Ex%5Cimplies%20x%3Dx%5Cimpliedby%20%5Ctextit%7Blet%27s%20use%20this%20cancellation%20rule%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Alog_e%5Cleft%28%20e%5E%7B%5Cfrac%7B4%7D%7B7%7D%7D%20%5Cright%29%5Ciff%20%5Ccfrac%7B4%7D%7B7%7D)