All categories

3 years ago

What is the leading coefficient of the polynomial?

Mathematics

1 answer:

ANEK [815]3 years ago

6 0

ANSWER

B) 15

EXPLANATION

The given polynomial is

$23 {x}^{5} + 12 {x}^{2} + 19 { x }^{3} + 15 {x}^{6}$

We arrange this polynomial in ascending powers of x to obtain the standard form;

$15 {x}^{6} + 23 {x}^{5} + 19 { x }^{3} + 12 {x}^{2}$

The degree of this polynomial is 6.

The coefficient of the leading term is 15

You might be interested in

Log base 5 (3) - log base 5 (5x) = 2

Sladkaya [172]

The answer is 3/125

$log_a(x) - log_a(y)=log_a( \frac{x}{y} ) \\ 
log_5(3) - log_5(5x) = log_5( \frac{3}{5x})$

$log_5( \frac{3}{5x})=2$

Since $log_b(x)=y$ is $b^{y} =x$ , then:
$log_5( \frac{3}{5x})=2$ is
$5^{2} = \frac{3}{5x} \\ 25 = \frac{3}{5x} \\ 5x*25=3 \\ 125x=3 \\ x=3/125$

5 0

3 years ago

10. Which ordered pair (x, y) is a solution of 3x +4y = 12?

svlad2 [7]

Answer:

C. (1, 2)

Step-by-step explanation:

3x + 4y = 12

3(1) + 4(2) = 12

3 + 8 = 12

12 = 12

3 0

3 years ago

What is <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B5%7D%20%29%5E%7B4%7D" id="TexFormula1" title="(\frac{1}{5} )^{4}"

DanielleElmas [232]

$\sf{Hey!}$

$\boxed{\underline{Question:}}$

$(\frac{1}{5})^4 = \frac{1}{632}$

If you want the decimal.

$^A^n^s^w^e^r^~:$

$0.0016.$

$\huge\bold{\textbf{\textsf{{\color{EXPLANATION :}{}}}}}$

Apply exponent rule: $(\frac{a}{b})^c =\frac{a^c}{b^c}$

= $\frac{1^4}{5^4}$

$1^4=1$

$=\frac{1}{5^4}$

$5^4=625$

= $\frac{1}{625}$

Hope It Helps. . .

$Answer~:$

$\sf{Jace}$

5 0

2 years ago

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

8 0

3 years ago

Read 2 more answers

Simplify to the lowest terms

Black_prince [1.1K]

Answer:

1/2

Step-by-step explanation:

divide the numerator & denominator by 4

4 0

3 years ago