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ch4aika [34]
3 years ago
10

What is the leading coefficient of the polynomial?

Mathematics
1 answer:
ANEK [815]3 years ago
6 0

ANSWER

B) 15

EXPLANATION

The given polynomial is

23 {x}^{5}  + 12 {x}^{2}  + 19 { x }^{3}  + 15 {x}^{6}

We arrange this polynomial in ascending powers of x to obtain the standard form;

15 {x}^{6} + 23 {x}^{5}    + 19 { x }^{3} + 12 {x}^{2}

The degree of this polynomial is 6.

The coefficient of the leading term is 15

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Log base 5 (3) - log base 5 (5x) = 2
Sladkaya [172]
The answer is 3/125

log_a(x) - log_a(y)=log_a( \frac{x}{y} ) \\ 
log_5(3) - log_5(5x) = log_5( \frac{3}{5x})

log_5( \frac{3}{5x})=2

Since log_b(x)=y is b^{y} =x, then:
log_5( \frac{3}{5x})=2 is 
5^{2} = \frac{3}{5x}  \\ 25 = \frac{3}{5x}  \\ 5x*25=3 \\ 125x=3 \\ x=3/125
5 0
3 years ago
10. Which ordered pair (x, y) is a solution of 3x +4y = 12?
svlad2 [7]

Answer:

C. (1, 2)

Step-by-step explanation:

3x + 4y = 12

3(1) + 4(2) = 12

3 + 8 = 12

12 = 12

3 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B5%7D%20%29%5E%7B4%7D" id="TexFormula1" title="(\frac{1}{5} )^{4}"
DanielleElmas [232]

\sf{Hey!}

\boxed{\underline{Question:}}

(\frac{1}{5})^4 = \frac{1}{632}

If you want the decimal.

^A^n^s^w^e^r^~:

0.0016.

\huge\bold{\textbf{\textsf{{\color{EXPLANATION :}{}}}}}

Apply exponent rule: (\frac{a}{b})^c =\frac{a^c}{b^c}

= \frac{1^4}{5^4}

1^4=1

=\frac{1}{5^4}

5^4=625

= \frac{1}{625}

Hope It Helps. . .

Answer~:

\sf{Jace}

5 0
2 years ago
The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

8 0
3 years ago
Read 2 more answers
Simplify to the lowest terms
Black_prince [1.1K]

Answer:

1/2

Step-by-step explanation:

divide the numerator & denominator by 4

4 0
3 years ago
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