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xeze [42]
3 years ago
15

What is the output of this code? import java.util.HashSet; class A { public static void main(String[ ] args) { HashSet set = new

HashSet(); set.add("A"); set.add("B"); set.add("C"); System.out.println(set.size()); } }
Computers and Technology
1 answer:
kompoz [17]3 years ago
5 0

Answer:

The code will give an error that is "At least one public class is required in main file".

Explanation:

In the given code if we do not use the public access modifier to the class. It will give an error so, the correct code to this question as follows:

Program:

import java.util.HashSet; //import package

public class A  //define class as public.

{

   public static void main(String[ ] args) //define main method.

   {

       HashSet set = new HashSet(); //creating hashset object.

       set.add("A"); //add alphabet in hashset

       set.add("B"); //add alphabet in hashset

       set.add("C"); //add alphabet in hashset

       System.out.print("Size of HashSet is :"set.size()); //print the size of hashset.

   }

}

Output:

Size of HashSet is : 3

Explanation of the program:  

  • In the above program, we define a public class that is "A" and inside the class, we define the main method.  
  • Inside the main method, we create a HashSet class object that is "set".  
  • To add elements in HashSet we use add() function that adds elements and in the last, we use the size() function that prints the size HashSet.
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Answer:

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Explanation:

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7 0
4 years ago
Which of the following are benefits of designing a scalable system? Choose 3 options.
zhenek [66]

Which of the following are benefits of designing a scalable system? Choose 3 options.

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3 years ago
PLS HURRY<br> Look at the image below
Nimfa-mama [501]

Answer:

20

Explanation:

During the first iteration for the list [1, 4], numB = 1.

During the first iteration of the list [2, 3], numA = 2.

answer = answer + numA + numB

= 0 + 2 + 1

= 3

Since the list [2, 3] is in a nested loop, we need to first finish iterating the whole list before numB iterates to the next number, so numA = 3 this time and numB still stays at 1.

answer = answer + numA + numB

= 3 + 3 + 1

= 7

Now, numB moves to 4 and numA starts back at 2 again.

answer = answer + numA + numB

= 7 + 2 + 4

= 13

numB still says at 4 and numA moves to 3 since it is in a nested loop:

answer = answer + numA + numB

= 13 + 3 + 4

= 20

print(answer) will print the output 20.

Hope this helps :)

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3 years ago
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Question 2 of 10
inn [45]

Answer:

b

Explanation:

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8 0
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