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4 years ago

• In your response, please include some examples of the three different types of storage.

Computers and Technology

2 answers:

babunello [35]4 years ago

6 0

Hard Disk Drive
Solid State Drive
And Random Access Memory (RAM)

Lynna [10]4 years ago

3 0

There are two type of storage. One retains all the data while powered but loses all data when unpowered, and the other retains data even when unpowered. An example of a temporary storage device is RAM. Some more permanent storage device includes Hard Disk Drives (HDD), Solid State Drives (SSD), CDs, and flash drives (also known as thumb drives). Not only do different storage devices store data for different amounts of time, they are also classified into three categories: primary, secondary, and tertiary. Primary storage is any storage directly attached to the memory bus. Secondary storage is any storage device that is not directly attached to the memory bus but still inside the computer. Tertiary storage is any storage device on the outside of the computer.

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A touch screen can be used as both an input device and output device. explain how this is possible

Evgesh-ka [11]

Well, Touch screen is only an input device as it only takes the input resistance(or capacitance in new touch screens) value as per the touch on the screen. And this value of resistance would determine the location of the touch on the screen.

The output work is done by the LCD or LED displays, which displays some images and texts on screen.

Touch Screen is only a transparent glass which is place on that display and synchronized with the LED displays such that user is able to 'touch' or have a 'sense of touch' on the actual displays

5 0

3 years ago

Information systems include all of these

Ulleksa [173]

Answer:

Explanation:

because you need people to access software through hardware and data through information and procedures.

4 0

3 years ago

C++ Code Outputs.

mojhsa [17]

Answer:

#include

using namespace std;

struct courseInfo{

string name;

int unit;

char grade;

};

struct Student {

string fName;

string lName;

string idNumber;

courseInfo courses[2];

int unitCompleted;

double gpa;

};

Student s;

bool openFile(ifstream &in);

void Print_info_one(Student s);

void Read_info(Student &s);

float Find_points(char c) ;

bool openFile(ifstream &inFile){

string line;

int i=0,k=0;

string fName="", lname="", id="", name1="", name2="";

char grade1, grade2;

int unit1, unit2;

if (inFile.is_open())

{

while (getline(inFile, line))

{

while (line[i] != ',')

{

fName += line[i];

i++;

}

i++;

while (line[i] != ' ')

{

lname += line[i];

i++;

}

i++;i++;

while (line[i] != ' ')

{

id += line[i];

i++;

}

i++;

int count=0;

while (count <2)

{

name1 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade1 = line[i];

i++;i++;

unit1 = line[i]-'0';

i++;i++;

count=0;

while (count <2)

{

name2 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade2 = line[i];

i++;i++;

unit2 = line[i]-'0';

}

inFile.close();

s.fName = fName;

s.lName = lname;

s.idNumber = id;

s.courses[0].name = name1;

s.courses[0].grade = grade1;

s.courses[0].unit = unit1;

s.courses[1].name = name2;

s.courses[1].grade = grade2;

s.courses[1].unit = unit2;

s.unitCompleted = unit1 + unit2;

s.gpa = (unit1*Find_points(grade1) + unit2*Find_points(grade2))/(unit1+unit2);

}

else

{

cout << "Error reading file\n";

return false;

}

return true;

}

void Print_info_one(Student s){

cout << "Name: " << s.fName << ", " << s.lName << " ID Number: " << s.idNumber << " Course 1 Name: " << s.courses[0].name << " Grade: "

<< s.courses[0].grade << " Units: " << s.courses[0].unit << " Course 2 Name: " << s.courses[1].name << " Grade: "

<< s.courses[1].grade << " Units: " << s.courses[1].unit << " Unit completed: " << s.unitCompleted << " GPA:" << s.gpa << endl;

}

void Read_info(Student &s){

}

float Find_points(char grade){

switch (grade)

{

case 'A':

return 4.0;

break;

case 'B':

return 3.0;

break;

case 'C':

return 2.0;

break;

case 'D':

return 1.0;

break;

case 'F':

return 0;

break;

default:

break;

}

return 0;

}

int main() {

ifstream inFile;

std::fstream fs;

fs.open ("input.txt", std::fstream::in );

Print_info_one(s);

return 0;

Explanation:

5 0

3 years ago

Effective collaboration requires a proactive and holistic strategy that integrates business goals and technology potential.

givi [52]

Answer:

a) true

Explanation:

Effective collaboration is a form of business organization strategy that is utilized by various firms, which is based on carrying out better collaborative or synergy software and proposes a visionary and holistic technique that incorporates company objectives and technology capability.

Hence, in this case, it is TRUE that effective collaboration requires a proactive and holistic strategy that integrates business goals and technology potential.

5 0

4 years ago

Using ________, GoPro encourages its millions of customers to submit their best content to the GoPro website to earn rewards and

coldgirl [10]

Answer:

UGC- User Generated Content

Explanation:

<em>It is a combination of making and user generated content a virtual shoe-tie for Go Pro. Go Pro has established a content marketing plataform able to grew into an extreme ecommerce success history. Instead of renting media company's audience, they use the brand-building services of millions of costumers.</em>

<em>The marketing team provide the tools and plataform to enable their costumers to share the videos and images they capture.</em>

5 0

3 years ago