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4 years ago

What % of 25 is 21?

Mathematics

2 answers:

Ierofanga [76]4 years ago

5 0

Answer: 84%

Step-by-step explanation:

1. Since 25 is the output value, we can assume that it is 100%

2. Now we out what we want to find with x

3. From step one, 25=100%

4. In the same line, x%=21

5. This gives us 2 equations:

100%=25(1)

x%=21(2)

6. By dividing equation 1 by equation 2 and taking note of the fact that both the left hand side of both equations have the same unit (%); we have (set up a proportion)

7. Then, take the reciprocal and solve. You should end up with x=84%

FinnZ [79.3K]4 years ago

3 0

Answer:

0.84

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3 years ago

Can y’all help me with this!???? I’ll boost you up!

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2 years ago

Let theta be an angle in quadrant II such that cos theta = -2/3

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Answer:

So we have $\csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}$ .

Step-by-step explanation:

Ok so we are in quadrant 2, that means sine is positive while cosine is negative.

We are given $\cos(\theta)=\frac{-2}{3}(\frac{\text{adjacent}}{\text{hypotenuse}})$ .

So to find the opposite we will just use the Pythagorean Theorem.

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Now to find $\csc(\theta)$ and $\tan(\theta)$ .

$\csc(\theta)=\frac{\text{hypotenuse}}{\text{opposite}}=\frac{3}{\sqrt{5}}$ .

Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).

So $\csc(\theta)=\frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{3 \sqrt{5}}{5}$ .

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What % of 25 is 21?​

What % of 25 is 21?