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oksian1 [2.3K]
2 years ago
13

HELP WITH THIS QUESTION, ASAP!!

Mathematics
1 answer:
alukav5142 [94]2 years ago
6 0
The answer to that question is b
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Is there an ordered pair that is a solution to BOTH of
Arte-miy333 [17]

Answer: The ordered pair is (2,3)

Step-by-step explanation:

To solve this problem, we can use substitution. With substitution, we substitute the y in each problem with the equations. In this case, x + 1 can substitute the y in y = -x + 5. Here is what the problem looks like now:

x + 1 = -x + 5

The reason we used substitution is because we assume that these linear equations are equal. We must prove it, though. We can use algebra.

Move the variables to one side and the numerical values to another:

x + x = 5 - 1.

Simplify.

2x = 4

Simplify.

x = 2.

Now, we got our x value, we can substitute it into our problem:

y = 2 + 1

y + -2 + 5

2 + 1 = - 2 + 5 = 3

Our x is 2, and our y is 3. The ordered pair that is a solution is (2,3).

6 0
3 years ago
Dolly is measuring the angles of a triangle. He measures the first two angles of a triangle and gets 30 and 100. How could he fi
Natalija [7]

Answer:

the third angle is 50 degress

Step-by-step explanation:

the angle sum property states that the sum of all the interior angles of a triangle is 180.

therefore : 30 + 100 + x = 180

x = 180 - 130

x = 50

8 0
2 years ago
Read 2 more answers
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
if your weekly salary is 1,015,how much do you have left each week after you pay for the following, rent - 443.50,cable tv - 23.
zheka24 [161]
Your answer would be $378.01
8 0
2 years ago
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The general form of the equation of a circle is Ax2 + By2 + Cx + Dy + E = 0, where A = B 0. If the circle has a radius of 3 unit
Lynna [10]
The correct answer is b.
8 0
3 years ago
Read 2 more answers
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