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lianna [129]
2 years ago
13

Jaishree studies for 5 hours daily. She devotes 2 hours of her time for science and mathematics. How muþch time does she devote

for other subjects ?​
Mathematics
2 answers:
baherus [9]2 years ago
8 0
  • Total time=5h
  • Time devoted for mathematics and science=2h

Let Time devoted for others be x

\\ \rm\Rrightarrow x+2=5

\\ \rm\Rrightarrow x=5-2

\\ \rm\Rrightarrow x=3h

Katyanochek1 [597]2 years ago
7 0

Answer:

3 hours

Step-by-step explanation:

All we need to do here is subtract to find out how many hours she has left to devote to other subjects.

5 - 2 = 3

Best of Luck!

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Answer:

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Parallel lines have the same slope.

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Express the complex number in trigonometric form -6 + 6sqrt3i
marusya05 [52]
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\large\begin{array}{l}\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the absolute value of z (complex modulus of z):}\\\\ \mathsf{|z|=\sqrt{a^2+b^2}}\\\\ \mathsf{|z|=\sqrt{(-6)^2+(6\sqrt{3})^2}}\\\\ \mathsf{|z|=\sqrt{36+36\cdot 3}}\\\\ \mathsf{|z|=\sqrt{36\cdot 108}}\\\\ \mathsf{|z|=\sqrt{144}}\\\\ \mathsf{|z|=12} \end{array}


\large\begin{array}{l}\bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Find the argument }\mathsf{\theta}\textsf{ of z:}\\\\ \mathsf{arg(z)=\theta}\\\\ \textsf{is an angle that satisfies the following conditions:}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{a}{|z|}=\dfrac{a}{\sqrt{a^2+b^2}}}\\\\ \mathsf{sin\,\theta=\dfrac{b}{|z|}=\dfrac{b}{\sqrt{a^2+b^2}}} \end{cases}\qquad\quad-\pi


\large\begin{array}{l}\textsf{For }\mathsf{z=-6+6\sqrt{3}\,i,}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{-6}{12}=-\,\dfrac{1}{2}}\\\\ \mathsf{sin\,\theta=\dfrac{6\sqrt{3}}{12}=\dfrac{\sqrt{3}}{2}} \end{cases}\\\\\\ \textsf{Since}\\\\ \mathsf{cos\,\theta0,}\\\\ \theta\textsf{ lies in the 2}\mathsf{^{nd}}\textsf{ quadrant.}\\\\\\\textsf{Therefore,}\\\\ \mathsf{\theta=\dfrac{2\pi}{3}~rad~~(120^\circ)} \end{array}


\large\begin{array}{l}\bullet~~\textsf{3}\mathsf{^{rd}}\textsf{ step: Express z in the trigonometric form:}\\\\ \begin{array}{rcl} \mathsf{z}&\!\!=\!\!&\mathsf{|z|\cdot (cos\,\theta+i\,sin\,\theta)}\\\\ \mathsf{-6+6\sqrt{3}\,i}&\!\!=\!\!&\mathsf{12\cdot \left(cos\, \dfrac{2\pi}{3}+i\,sin\,\dfrac{2\pi}{3}\right)\qquad\quad\checkmark} \end{array} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154167


\large\textsf{I hope it helps.}


Tags: <em>complex number trigonometric form trig absolute value modulus argument angle</em>

4 0
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kompoz [17]
Hello there! I can help you! The number shows is 24 ten millionths. It is in decimal form, so the exponent for the power of 10 will definitely be negative. The first number has to be greater than or equal to 1, but less than 10. If we look at this number and you place the decimal between the 2 and the 4, we can use 2.4 as the front number, because it's greater than 1, but less than 10. Now, we can move that decimal to the left a certan number of times to get that number shown below. If you count from the decimal, you move to the left 6 times. That makes the power of ten 10^-6. And when you multiply 2.4 * 10^-6 (0.000001), you get 0.0000024. There. The number in scientific notation is 2.4 * 10^-6.
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3 years ago
Read 2 more answers
AP CALC HELP!!! Worth 38 points. AP Calc AB differental FRQ
sveta [45]

Answer:

5a.  approximately 6 grams remain after 2 seconds

5b.  The graph shown cannot be a solution. The solution has negative slope everywhere.

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5d.  The amount is changing at a decreasing rate. (As y gets smaller, so does the magnitude of dy/dt.)

Step-by-step explanation:

5a. The tangent line has the equation ...

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Here, that is

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Then at t=2, the value is ...

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__

5b. y² is always positive (or zero), so -0.02y² will be negative. This is dy/dt, the slope of the curve with respect to time, so any curve with positive slope somewhere cannot be a solution.

__

5c. The equation is separable so can be solved by integrating ...

  ∫y^-2·dy = -0.02∫dt

  -y^-1 = -0.02t +c . . . . for some arbitrary constant c

Multiplying by -50 gives ...

  50/y = t + c . . . . for some constant c

We can find the value of c by invoking the initial condition. At t=0, y=10, so we have ...

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Then, solving for y, we get ...

  y = 50/(t+5)

__

5d. As noted above (and as described by the differential equation), the magnitude of the rate of change is proportional to the square of y. As y decreases, its rate of change will also decrease (faster). You can see that the curve for y flattens out as t increases. The amount of the substance is changing at a decreasing rate.

5 0
3 years ago
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