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frez [133]
3 years ago
11

During the Playoff the schools football team has on average 30% their games than during the regular season. The average for this

year's playoffs attendance was 15,600 fans. How many fans were there on average during a regular season game
Mathematics
2 answers:
exis [7]3 years ago
5 0

Answer:12000

Step-by-step explanation:

During the Playoff the schools football team has on average 30% their games than during the regular season

The average for this year's playoffs attendance was 15,600 fans

To get the number of fans during a regular season goes thus:

Since there is an increase of 30%, we add 100% to 30% which gives:

100% + 30% = 130%

= 15600 ÷ 130%

= 15600 ÷ 130/100

= 15600 × 100/130

= 15600 × 0.7692

= 12000

There are 12000 fans during a regular season

Fiesta28 [93]3 years ago
4 0

Answer:

it

Step-by-step explanation:

i just did it

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Mr. Roberts will spend $132 on a painting

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3 years ago
A line has a slope of 2. Write an equation in slope intercept form for the line that is perpendicular to this line.
notsponge [240]

Hey there!

A perpendicular line's slope to another line is always the negative reciprocal of slope.

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I hope that this helps! Have a great day!

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3 years ago
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The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th
makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 e^{kt}

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070  e^{3k}

\frac{9000}{4070} = e^{3k}

\frac{900}{407}=e^{3k}

<u><em>Taking natural logarithm on both sides, we get:</em></u>

ln\frac{900}{407}=ln(e^{3k})

ln\frac{900}{407}= 3k ln<em>e</em>

ln<em>e</em>=1

ln \frac{900}{407}= 3k

or k = \frac{1}{3}ln\frac{900}{(407)}

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7 0
3 years ago
I need help with this one too
natali 33 [55]

Hey there! :)

Answer:

y = 11.

Step-by-step explanation:

Set both of the equations equal:

5x - 9 = x² - 3x + 7

Rearrange the equation:

0 = x² - 3x - 5x  + 9  + 7

Combine like terms:

0 = x² - 8x + 16

Factor:

0 = (x -4)²

Solve for x:

0 = x - 4

x = 4.

Plug this into an equation to solve for 'y':

y = 5(4) - 9

y = 20 - 9

y = 11.

3 0
3 years ago
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Please help!! (math)
olga55 [171]

Bro answer.

Step-by-step explanation:

This is the step of doing this so write this in class 10 we do like this ok

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2 years ago
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