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garik1379 [7]
3 years ago
5

The graph for the equation y=-x+2 is shown. If another equation is graphed so that the system has an infinite number of solution

s, which equation could that be?
A. y=-2(x-1)
B. y=-(x+2)
C. y=-1/4(4x-8)
D. y=-1/2(x+4)
Mathematics
2 answers:
maks197457 [2]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Note that C is exactly -1/4(4x-8) = -1/4*4x -1/4*(-8) = -x+2, so the system with C is the same equation twice, and obviously has an infinite number of solutions.

SOVA2 [1]3 years ago
4 0

Answer: C

Step-by-step explanation:

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gulaghasi [49]

Answer:

I didnt get what the photo shows....

Step-by-step explanation:

7 0
3 years ago
This problem is only for smart kids, all people who dont do it r babies
Phantasy [73]

Answer:

46

Step-by-step explanation:

∠DAC ≅ ∠ACB because they are opposite interior angles where transversal AC crosses parallel lines BC and AD.

∠DAC ≅ ∠CAB because they are corresponding angles of the similar triangles ΔABC and ΔACD.

Hence ∠ACB ≅ ∠CAB and ΔABC is isosceles with side lengths both being 9. The corresponding side lengths of ΔACD are 12, meaning the base of ΔABC, segment AC, is 12. The scale factor of ΔACD to ΔABC is then 12:9 = 4:3, so the base AD of ΔACD is (4/3)×12 = 16.

So, the side lengths of the trapezoid are ...

  • AB = 9
  • BC = 9
  • CD = 12
  • DA = 16

and the perimeter is 9 +9 +12 +16 = 46 units.

3 0
4 years ago
X3(2x2 + 3x) <br><br> a. 2x5 + 3x4 <br> b. 5x9 <br> c. 2x6 + 3x3 <br> d. 5x
Serhud [2]

Answer:

2x^5+3x^4

Step-by-step explanation:

x^3\left(2x^2+3x\right)

<u>Apply distributive law: </u>a\left(b+c\right)=ab+ac

  • x^3\left(2x^2+3x\right)=x^3\times \:2x^2+x^3\times \:3x
  • x^3\times \:2x^2+x^3\times \:3x
  • 2x^5+3x^4

<u>OAmalOHopeO</u>

5 0
3 years ago
The number of stamps that Kaye and Alberto had were in the ration of 5:3 respecctively. After Kaye gave Alberto 10 of her stamps
masha68 [24]

Answer:  The correct option is

(D) 60.

Step-by-step explanation:  Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.

After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.

We are to find the number of stamps that Kaye had more than Alberto.

Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.

Then, according to the given information, we have

(5x-10):(3x+10)=7:5\\\\\Rightarrow \dfrac{5x-10}{3x+10}=\dfrac{7}{5}\\\\\Rightarrow 25x-50=21x+70\\\\\Rightarrow4x=120\\\\\Rightarrow x=\dfrac{120}{4}\\\\\Rightarrow x=30.

So, the number of stamps that Kaye had = 5 × 30 = 150

and

the number of stamps that Alberto had = 3 × 30 = 90.

Therefore, the number of stamps that Kaye had more than Alberto is

150-90=60.

Thus, Kaye had 60 stamps more than Alberto.

Option (D) is CORRECT.

7 0
3 years ago
The square pqrs is shown.
ira [324]

Answer:

1:1

Step-by-step explanation:

The ratio would be 1:1 since it's a square, the sides will always be the same. In a square ,all sides are the same length. If they are not, then it wouldn't be a square.

5 0
3 years ago
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