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olga2289 [7]
3 years ago
10

A $15,000, 6 percent , 50-day note ,dated November 8, is discounted at 5 percent on November 28, the proceeds of the note would

be?
A. $14,936,46
b. $ 15,610,64
c. $63,54
d. $15,061,98
Mathematics
2 answers:
tatyana61 [14]3 years ago
5 0
The answer is the D option.
steposvetlana [31]3 years ago
4 0

Answer:

D. $15061.98

Step-by-step explanation:

In order to calculate the proceeds we will using the following computation:

Principal + {Principal * Discounted rate * Frequency of a year on Maturity Date}

15,000 + {15,000 * 5% * (30/365)}

Hence, the proceeds of note would be $15,061.98

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15 POINTS HELP!! Identify the y-intercept for the line of the equation below. Show your work
Inessa05 [86]
8x-2y=12
-2y=-8x+12
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y=4(0)-6
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(0,-6)
4 0
3 years ago
PLEASE HELP ME ASAP!!!
rjkz [21]

Answer:

d) 7^{14}

Step-by-step explanation:

we simplify (7^{7})^{2} by doing 7 x 2 = 14

so it is now

7^{14}

to check, we can use a calculator.

7 to the power of 14 = 678223072849

and

7 to the power of 7, squared also = 678223072849

Hope this helps!

7 0
2 years ago
Please Help ! Will Reward Brainliest
pychu [463]

I think 42

would be the best answer to your question in my opininon.


7 0
3 years ago
Subtract 8 1/2 - 2 2/3 = ?
Andrews [41]

Answer: 2 2/3 or 2.6 repeating

Step-by-step explanation:

- Reduce the numbers With the greatest common divisor 2

- Calculate product

- Calculate the difference

- YOUR FINAL ANSWER

Hope I was able to satisfy your needs

8 0
3 years ago
Read 2 more answers
For X a binomial random variable with n=5 and p=1/4, answer the following
mash [69]
Recall that for X\sim\mathrm{Bin}(n,p), i.e. a random variable X following a binomial distribution over n trials and with probability parameter p,

\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}

So you have

\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26

\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)
=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}
=\dfrac{375}{1024}\approx0.37

The expected value of X\sim\mathrm{Bin}(n,p) is simply np, while the standard deviation is \sqrt{np(1-p)}. In this case, they are \dfrac54=1.25 and \sqrt{\dfrac{15}{16}}\approx0.97, respectively.
7 0
3 years ago
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