Answer:
When the volume of a gas in a container varies inversely with the pressure on the gas and a container of nitrogen has a volume of 29.5 litres with 2000 psi. So, if the tank has a 14.7 psi pressure, then the volume of the tank would be 4013.6 litres.
Step-by-step explanation:
- The volume of a gas in a container varies inversely with the pressure on the gas. If a container of nitrogen has a volume of litres with psi, what is the volume if the tank has a psi pressure.
- Calculate the volume to the nearest whole number.
- Use the given values and calculate the proportionality constant as well as required solution.
Step 1 of 2
Write the inversely proportionality relation between the volume and pressure of a gas in container.
Where volume is represented by v and pressure is represented by p.
Remove the proportionality and place a constant say k.
Substitute the given values of nitrogen that v=29.5 and
p=2000 and calculate the value of k from above equation.
Step 2 of 2
Substitute the value p=14.7 and above calculated k value in the equation
<span> we know the length of the cable is 9m.
That means the magnitude of </span><span><span>r<span><span><span>AB</span></span><span></span></span></span>=9</span><span>m.
The unit vector, denoted u, is each of </span><span>r<span><span><span>AB</span></span><span></span></span></span><span> divided by the magnitude.
</span>u=<span>(<span><span>x/9</span><span></span></span>i−<span>y/9<span></span></span>j−<span>z/9<span></span></span>k<span>)
</span></span><span>We can also figure out the unit vector of F.
</span>u=(350i - 250j - 450k)/√(350² +(-250)² +(-450)²)
u=0.562i−0.401j−0.723<span>k
</span>
<span>Force F is directed from point A to B, then both unit vectors must be equal.
Therefore
</span>(x/9i−y/9j−z/9k)=0.562i−0.401j−0.723k
<span>We can now solve for each term
x/9=0.562----- > x=5.058 m
-y/9=-0.401--------- > y=3.609 m
-z/9=-0.723------- > z=6.507 m
The answer is
the coordinates of point a
(5.058,3.609,6.507)
</span>
Step-by-step explanation:
A bar graph serves to visibly represent the frequency of a series of events.
To create a bar graph you can draw on the horizontal axis, each one of the events, and on the axis to verticate the frequency of occurrence.
For this case the possible events are the values from 1 to 5 of the numbered sequence
1 2 3 4 5
The frequency for each number is
4 6 2 6 2.
With these values, a bar graph was made in excel, which is shown in the attached image.
There it is observed that the events with greater frequency are the 4 and the 2.
Sum of two integers with different signs is equal to 8.
There are several answers:
+12 and -4
+10 and -2
+11 and -3
ETC.