2 years ago

What is the area of a regular pentagon with a side of 20 inches? can you explain?

Mathematics

1 answer:

san4es73 [151]2 years ago

6 0

here is the answer: A≈688.19in²

I cant really give you an explanation though

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Write x2 − 8x + 13 = 0 in the form (x − a)2 = b, where a and b are integers

Marrrta [24]

X^2 - 8x + 13 = 0
subtract 13 from both sides
x^2 - 8x = -13
-8/2 = -4, (-4)^2 = 16, add 16 to both sides
x^2 - 8x + 16 = -13 + 16
factor the left side
(x - 4)^2 = 3

3 0

3 years ago

What is the solution to the equation 3/5(x-5/8)=1/12-x+7/8?

olga_2 [115]

x = 5/6 = 0.833.................

8 0

3 years ago

I need help pls!

vredina [299]

Answer:

Step-by-step explanation:

7 feet 1 foot is 12 inches

7*12= 84 inches.

None of the choices are correct.

90 inches is 7.5 feet

62.5 inches is 5.2 feet

75 inches is 6.25 feet

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2 years ago

Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross

AleksandrR [38]

Answer: See below

Step-by-step explanation:

To find the factor,

f(x) = 0

$\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}$

So,

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

Therefore,

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

7 0

2 years ago

I need help

pashok25 [27]

Step-by-step explanation:

[ Refer to the attachment ]

Q 1 was not clear but yet !!

8 0

2 years ago