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AlladinOne [14]
3 years ago
15

The number of 7th graders attending Middle field Science Academy this year is 130% of last year’s total. If 500 7th graders atte

nded last year, how many attend this year? A tape diagram. There are 130 students who are 7th graders this year out of 100 who were 7th graders last year. There are question mark students this year out of 500 who were 7th graders last year. Which steps should be used to find 130% of 500? Check all
Mathematics
2 answers:
podryga [215]3 years ago
6 0

Answer:

B. (100)(5)=500 C.(130)(5)=650 D.130/100= 650/500 E. There are 650 7th graders this year

Step-by-step explanation:

Just took it on Egde

rodikova [14]3 years ago
6 0

Answer:

its b,c,d,e

Step-by-step explanation:

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2 years ago
PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.
anygoal [31]

Option C: x=0 and x=\frac{5}{2} are the solutions.

Explanation:

The equation is \frac{x}{3} =\frac{x^{2} }{x+5}

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, x=0 and x=\frac{5}{2} are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute x=0 in the original equation to check whether both sides of the equation are equal.

\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}

Thus, both sides of the equation are equal.

Hence x=0 is a true solution.

Now, Let us substitute x=\frac{5}{2} in the original equation to check whether both sides of the equation are equal.

\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}

Thus, both sides of the equation are equal.

Hence, x=\frac{5}{2} is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0
3 years ago
To get from his house to the lecture hall at school, Lin walked west 651 feet. After class, he walked northeast 910 feet to the
Ahat [919]

The general direction that Lin walked from the gym to his house is; B: Lin walked southwest, creating an obtuse triangle.

<h3>How to interpret distance bearing?</h3>

We are given;

Distance between the lecture hall and gym = 910 feet.

Distance between the gym and Lin apostrophe's house = 615 feet.

Distance between the lecture hall and Lin apostrophe's house = 651 feet.

Now, since this 3 distances form a triangle and the 3 distances are unequal, then we can call it an obtuse triangle since he walked west and then walked northwest.

Now, since he walked back to his house from the gym, we can say that he walked southwest if we picture the bearing of his first two directions.

Read more about Distance Bearing at; brainly.com/question/22719608

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2 years ago
Find the graph of the inequality y&gt;-(1/6)x+1.
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Answer:

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Step-by-step explanation:

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