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Mkey [24]
3 years ago
9

Will give brainliest: Analyze the graph of the given polar curve. If possible, describe the shape of the graph (circle, rose cur

ve, limacon, etc), and state the domain, range, and maximum r-value of the graph. State whether the graph is continuous and whether it is bounded. Describe any symmetry the graph has. Give the equations of any asymptotes or state that the graph has no asymptotes.
r = -2 cos 5θ

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

Step-by-step explanation:

• The shape of the curve is a rose curve.

• The domain are real numbers

• And the range is approximately from -2 to 2

The maximum value of r on the graph is 2

• Yes the graph is continuous and it is bounded above and below

• The graph is symmetrical about the x axis and not about the y axis.

• No asymptotes

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Answer:can i have more information about the question than i can solv it as soon as i get it

Step-by-step explanation:

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To motorists leave from the same point at the same time, one traveling east at 36 MPH and the other traveling west at 44 MPH. Ho
Ber [7]
This is a very good question to know about. People who make tests really like it.

The way to solve it is to make the slower car stop and use the difference in speed = to the rate. then do it as an ordinary d = r*t problem.

The difference in speeds  is 44 - 36 = 8 miles/ hour.
d = 260 miles
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3 years ago
Find the sum of a finite geometric series.
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Answer:

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I need Help q real quick
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8 0
3 years ago
Read 2 more answers
The hypotenuse of a right triangle is 24 ft. long. the length of one leg is 44 ft. more than the other. find the lengths of the
Mekhanik [1.2K]
The way to solve the missing side of a right triangle is normally by the Pythagorean Theorem:
{a}^{2}  +  {b}^{2}  =  {c}^{2} \\  {a}^{2}  =  {c}^{2}  -  {b}^{2}  \:  \infty  \: \sqrt{ {a}^{2} }  = \sqrt{( {c}^{2}  -  {b}^{2}) } \\ a= \sqrt{( {c}^{2}  -  {b}^{2}) }
where c always is the hypotenuse
So c = 24 ft
b = 44 + a
{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\  {a}^{2}  +  {(a + 44)}^{2}  =  {24}^{2}  \\  {a}^{2}  +  {a}^{2}  + 88a + 1936 = 576
Now combine like terms:
2{a}^{2}  + 88a + 1936 = 576 \\  2{a}^{2}  + 88a + 1936 - 576 = 0 \\ 2{a}^{2}  + 88a + 1360 = 0
Now we have to try to factor this quadratic equation, first let's take out 2:
2({a}^{2}  + 44a + 680) = 0
we need factors of 680 whose sum = 44
20×34, 10×68, 17×40
however... 20+34=54, 10+68=78, 17+40=57
So we will need to use the quadratic equation unfortunately :(
x = ( - b +  -  \sqrt{( {b}^{2}  - 4ac)}) \div 2a
Now the "x" is actually our "a", the a is 1, b is 44, c is 680
a = ( - 44 +  -  \sqrt{( {44}^{2}  - 4(1)680)})  \\ \div  \: 2(1) \\  a = ( - b +  -  \sqrt{(1936 - 2720)}) \\  \div  \: 2
a = ( - 44 +  -  \sqrt{(-784)}) \\  \div  \: 2  =  - 44 \div 2 \:  +  - (i \sqrt{784}) \div 2 \\ a =  - 22 +  - i \sqrt{16}  \sqrt{49}  \div 2 \\
a =  - 22 +  - 28i \div 2  \\ a =  - 22 +  - 14i
not quite sure where to go from these imaginary numbers...
I DON'T THINK A RIGHT TRIANGLE WITH THOSE DIMENSIONS IS POSSIBLE







8 0
3 years ago
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