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Oksanka [162]
3 years ago
10

What is the radius of the circle x2 + y2 -1=0?

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0

Answer:

radius = 1

Step-by-step explanation:

x^2 + y^2 -1=0

Add 1 to each side

x^2 + y^2 -1+1=0+1

x^2+y^2 = 1

This is written in the form

(x-h)^2 + (y-k)^2 = 1^2  where (h,k) is the center and r is the radius

The center is (0,0) and the radius is 1

Montano1993 [528]3 years ago
5 0

Answer: 1

Step-by-step explanation:

rewrite x^2 + y^2 -1 = 0 as x^2 + y^2 = 1

the 1 on the right hand side of the equation is equal to the radius squared

1 = r^2

r = 1

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Please help me find out the process to find y for the first three questions and tell me what y is
Sliva [168]

Answer:

1. y = 14.718

2. ??

3. y = 39.794°

Step-by-step explanation:

<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function: </em>

SOH...

 Sine: sin(θ) = Opposite / Hypotenuse

...CAH...

 Cosine: cos(θ) = Adjacent / Hypotenuse

...TOA

 Tangent: tan(θ) = Opposite / Adjacent

1. Sine: sin(θ) = Opposite / Hypotenuse

sin(42°) = y / 22

so on your calculator enter 42 then sin = 0.669

0.669 = y/22      multiply both sides by 22 to get y

y = 14.718

2. is there any other information??

3. The two sides we know are Opposite 40 and Adjacent 48.

SOHCAHTOA tells us we must use Tangent.

Calculate Opposite/Adjacent = 40/48 = 0.833

Find the angle from your calculator using tan-1

Tan y° = opposite/adjacent = 40/48 = 0.833  

tan-1 of 0.833 = 39.794°

7 0
3 years ago
I need help please help me im struggling please show WORK and tell me how to do it NO links please.
stellarik [79]

Answer:

- 7y +3 =-25

-7y=-25—3

-7y=-28

-7y÷-7= -28÷-7

y=4

Step-by-step explanation:

Take +3 to the side so that your variable and a constant is on their own sides. When a number goes over the equals sign the sign changes at becomes the inverse that's why l said - 3. You now calculate - 25—3 equals 28 then divide by 7 to find y and your y is 4.

3 0
3 years ago
The least common multiple of two numbers is 60 and one of the numbers is 7 less than the other number.What are the numbers.Justi
denis-greek [22]

Answer:

As the least common multiple of two numbers is 60 , the two numbers are factors of 60 . Among {1,2,3,4,5,6,10,12,15,20,30,60} , 3 & 10 and 5 & 12 are the only two pair of numbers whose difference is 7 . But Least common multiple of 3 and 10 is 30

6 0
2 years ago
Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6
Anton [14]

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

V= \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder,x^{2}+y^{2} =1 and the ellipsoid, 4x^{2}+ 4y^{2} + z^{2} =64

In polar coordinates, we know that

x^{2}+y^{2} =r^{2}

So, the ellipsoid gives

4{(x^{2}+ y^{2)} + z^{2} =64

4(r^{2}) + z^{2} = 64

z^{2} = 64- 4(r^{2})

z=± \sqrt{64-4r^{2} }

So, the volume of the solid is given by:

V= \int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta

= 2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta

To solve the integral take, 64-4r^{2} = t

dt= -8rdr

rdr = \frac{-1}{8} dt

So, the integral  \int\ r\sqrt{64-4r^{2} } rdr become

=\int\ \sqrt{t } \frac{-1}{8} dt

= \frac{-1}{12} t^{3/2}

=\frac{-1}{12} (64-4r^{2}) ^{3/2}

so on applying the limit, the volume becomes

V= 2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta

=\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta

V = \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Since, further the integral isn't having any term of \theta.

we will end here.

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0
2 years ago
Let f(x) = 6x2 + 5 and g(x) = 3x-5. Find g(f(0))
devlian [24]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
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