Answer:
Step-by-step explanation:
BCF and DCA
Given:
JH = 3.2 feet
IJ = 5 feet
∠J = 90°
To find:
Angle of I to the nearest tenth
Steps:
In this triangle we know, base length and height but we don't know the hypotenuse of the triangle. So we will use tangent as it only requires height and base length
Tan x =
Tan x =
Tan x =
Tan x = 0.64
x =
Now using the natural tangent table or arctan calculator, we find
x = 32.6°
Therefore, the measure of angle I is 32.6°.
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Answer:
The equation is y = 3x + 2
Step-by-step explanation:
The form of the linear equation is y = m x + b, where
- m is the slope of the line which represent the equation
- b is the y-intercept which is value y at x = 0
The rule of the slope is m = Δy/Δx, where
- Δx = x2 - x1 and Δy = y2 - y1
- (x1, y1) and (x2, y2) are two points on the line.
∵ x is the input
∵ Input: 0, 1, 2, 3, 4
∵ y is the output
∵ output: 2, 5, 8, 11, 14
∴ The points on the line are (0, 2), (1, 5), (2, 8), (3, 11), and (4, 14)
→ Use any two points to find m
∵ x1 = 0 and y1 = 2
∵ x2 = 1 and y2 = 5
→ Find Δx and Δy
∴ Δx = 1 - 0 = 1
∴ Δy = 5 - 2 = 3
→ Substitute them in the rule of the slope above
∵ m =
∴ m = 3
∵ b is the value of y at x = 0
∵ At x = 0, y = 2
∴ b = 2
→ Substitute the values of m and b in the form of the equation above
∵ y = 3x + 2
∴ The equation is y = 3x + 2
answer: the answer is 7.23 because you subtract the other numbers from 27.22