Answer:
For both figures ![A=4+2+2+1=9\ units^{2}](https://tex.z-dn.net/?f=A%3D4%2B2%2B2%2B1%3D9%5C%20units%5E%7B2%7D)
Step-by-step explanation:
we know that
The area for both composite figures is equal to the area of a square plus the area of two isosceles right triangles plus the area of a smaller isosceles triangle
so
<em>Area of the square</em>
![A=2^{2}=4\ units^{2}](https://tex.z-dn.net/?f=A%3D2%5E%7B2%7D%3D4%5C%20units%5E%7B2%7D)
<em>Area of the isosceles right triangle</em>
![A=(1/2)(2)(2)=2\ units^{2}](https://tex.z-dn.net/?f=A%3D%281%2F2%29%282%29%282%29%3D2%5C%20units%5E%7B2%7D)
<em>Area of the smaller isosceles triangle</em>
![A=(1/2)(2)(1)=1\ units^{2}](https://tex.z-dn.net/?f=A%3D%281%2F2%29%282%29%281%29%3D1%5C%20units%5E%7B2%7D)
The area of the composite figure is
![A=4+2+2+1=9\ units^{2}](https://tex.z-dn.net/?f=A%3D4%2B2%2B2%2B1%3D9%5C%20units%5E%7B2%7D)
Answer:
see explanation
Step-by-step explanation:
the equation of a line in slope- intercept fprm is
y = mx + b ( m is the slope and b the y-intercept )
y =
x - 4 is in this form
with m =
and b = - 4
Plot the point (0, - 4)
using the slope add 5 to the y-coordinate and 4 to the x-coordinate
(0, - 4 ) → (0 + 4, - 4 + 5) → (4, 1) ← point on the line
Plot the points (0, - 4) and (4, 1) and draw a straight line through them to obtain a sketch of the graph
It would be c because I used a graphing calculator lols