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2 years ago

What is 140 rounded to the nearest tenth of a percent

Mathematics

1 answer:

Ierofanga [76]2 years ago

3 0

140 changed to a percent would be 1.4 (divide by 100), and rounded the nearest tenth would be 1.4.

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2 years ago

Which digit is in the ten thousandths place in 4,6037?

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Step-by-step explanation:

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2 years ago

Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

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Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

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2 years ago

Can someone please help me with this, it’s urgent!!

olga nikolaevna [1]

Answer:

B n D

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

15 - 3k = 10(k-5) Can someone please answer this

solmaris [256]

Answer:

k = 5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Step-by-step explanation:

Step 1: Define equation

15 - 3k = 10(k - 5)

Step 2: Solve for k

Distribute 10: 15 - 3k = 10k - 50
Add 3k to both sides: 15 = 13k - 50
Add 50 to both sides: 65 = 13k
Divide 13 on both sides: 5 = k
Rewrite: k = 5

Step 3: Check

Plug in k into the original equation to verify it's a solution.

Substitute in k: 15 - 3(5) = 10(5 - 5)
Subtract: 15 - 3(5) = 10(0)
Multiply: 15 - 15 = 0
Subtract: 0 = 0

Here we see that 0 does indeed equal 0.

∴ k = 5 is a solution of the equation.

5 0

2 years ago

Read 2 more answers