How do I find x and y in this equation

Mathematics

1 answer:

zalisa [80]3 years ago

7 0

X= 8 radical 5 and y= 8 radical 10

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The coordinates of point P on a coordinate grid are (−5, −6). Point P is reflected across the y-axis to obtain point Q and acros

Llana [10]

Hey friend!
Let's figure this out!

P(−5, −6)
reflect about y axis
Q(5, -6)
reflect about x axis
R(5,6)

So that gives you the answer!
3. Q(−5, 6) and R(5, −6)

Hope this helped!

4 0

3 years ago

Read 2 more answers

Jesse buys a necklace that is on sale for 25% off the original price is 119.50 if tax is 7% what is the total price that Jesse w

trapecia [35]

Answer:

$95.89875

Step-by-step explanation:

The original price of the necklace is 119.5. And we are subtracting 25% from this. 119.5 - 25% = 119.5 - 1/4 since 25% is 25/100 which is also 1/4.

So without tax, the price of the necklace is 119.5 - 29.875 which is 89.625.

The tax is 7%. So we should add 89.625 to 7%. This is complicated, but it should result in 95.89875.

If we round this to the nearest cent, it should be <em>$95.9</em>.

6 0

2 years ago

If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3

yulyashka [42]

Hello,

$L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\$

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The below shows the cost of items sold at Luke's electronics. Which two items would represent the ratio 3:1

Ugo [173]

The blue ray and the tv combined is 490 so just divide by 2 there’s your answer bud

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2 years ago

P(A)=0.45, P(A∩B)=0.15 and P(B\A)=0.25 what is the value of P(A\B)

Fiesta28 [93]

Answer:

0.35? That is correct?

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3 years ago