All categories

3 years ago

Giving 50 points for both pages + brainlest for first answer

Mathematics

1 answer:

beks73 [17]3 years ago

4 0

Answer:

1) Put a circle on the 1 and make an arrow all the way down to the left of the 1. Then put a circle on the 8 and make an arrow all the way down to the 10.

2) Put a colored in circle on the 6 and make an arrow to right all the way down to the 10. Then put a circle(thats not colored in) on the 4 and make an arrow to the right all the way down to the -10.

3) Put a colored circle on the -6 and 4

Step-by-step explanation:

I hope this helps!!!

Have a wonderful dayyy!!

You might be interested in

Help me please I beg if you can

Virty [35]

Answer: The mean is 3780

Step-by-step explanation:

Mean is found by adding all values and dividing the sum by how many values were added.

4250+4019+3895+3739+3401+3376=22680
22680/6=3780

6 0

3 years ago

F(1) = -3<br> f(n) = 2 · f(n − 1) +1<br> f(2)=

raketka [301]

Answer:

-5

Step-by-step explanation:

f(2) = 2 * f(1) + 1

f(2) = 2 * -3 + 1

f(2) = -6 + 1

f(2) = -5

6 0

3 years ago

What is 0.08 divided by 1.44

hammer [34]

0.08 divided by 1.44 is 0.055555556

6 0

3 years ago

A square has a area of 466.56m squared work out the peremiter

MissTica

Answer:

Perimeter = 86.4 (m)

Step-by-step explanation:

A square (with side x) has an area of 466.56 (m^2)

=> x^2 = 466.56

=> x = sqrt(466.56) = 21.6

=> Perimeter of this square: P = 4(x) = 4(21.6) = 86.4 (m)

Hope this helps!

3 0

3 years ago

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error