Answer: C. Reformation
Explanation: A non-compete agreement or clause is a legal binding entered into by two or more parties which restricts the parties from being in competition with the other usually through the sale of similar product. However, in the context above, since the non-compete clause has been breached by Jack, and the judge feels the time constraint in the clause was unreasonably long, The reformation process will be best to remediate the situation, which refers to the change or alteration of the terms of an existing document using the judicial process and requires the conformation of the parties involved.
Answer:
The Journal entries are as follows:
(i) Sale of Equipment
Cash A/c Dr. $20,300
Accumulated Depreciation A/c Dr. $22,500
To Equipment $40,000
To Gain $2,800
(To record the sale of equipment)
(ii) Sale of Equipment
Cash A/c Dr. $12,700
Accumulated Depreciation A/c Dr. $22,500
Loss A/c Dr. $4,800
To Equipment $40,000
(To record the sale of equipment)
Workings:
Accumulated Depreciation = [(40,000 - 2,500) ÷ 5] × 3 years
= 7,500 × 3 years
= $22,500
They can set good examples of people who practiced savings and the result it gave them. Provide seminars of the results and actual computation of savings through targeted years and the possible assets that they may possess through savings. It can also help them avoid some financial problems that they might encounter.
Answer:
The probability that 2 or 3 customers will arrive in a 15-minute period is 0.4703
Explanation:
Firstly, we have to determine the segment unit, since the mean is 10 per hour, the segment unit is 1 hour.
The mean(m) = 10
since the period is 15 minutes = 0.25 hour, t= 0.25 hour / 1 hour. Therefore mt= 2*10 = 2.5
The poisson distribution formula P(x) = 
Therefore the probability that 2 or 3 customers will arrive in a 15-minute period
P(x=2) or P(x=3) = P(x=2) + P(x=3) = 
= 0.2565 + 0.2138 = 0.4703
Therefore P(x=2) or P(x=3) = 0.4703
The probability that 2 or 3 customers will arrive in a 15-minute period is 0.4703
