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Vlad [161]
3 years ago
6

Ten times the sum of half a number and 6 is 8

Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0
Let the required number is 2x ,





According to the condition,



➡ 10 times the sum of half of 2x and 6 = 8

= > 10 \times ( \frac{2x}{2} + 6) = 8 \\ \\ \\ = > 10 \times (x + 6) = 8 \\ \\ \\ = > 10x + 60 = 8 \\ \\ \\ = > 10x = 8 - 60 \\ \\ \\ = > 10x = - 52 \\ \\ \\ = > x = - \frac{ 52}{10} \\ \\ \\ = > x = - 5.2



Therefore the value of x is -5.2


And, required number is -5.2
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a) P (x) = (x + 3) (x-1) (x-4)

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<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

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Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
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