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Evgesh-ka [11]
3 years ago
7

Which two days had a ratio of 2:5 computers sold? Looking for brainliest.

Mathematics
2 answers:
Marianna [84]3 years ago
8 0

Answer:  A. Wed to Fri

We have a bunch of natural numbers and we're told a pair is in the ratio 2:5.

For natural numbers to have this ratio, the left number will be a multiple of two and the right number will be a multiple of five.

Our only option for a multiple of 5 is 15, Friday.  So we have

2:5 = x:15

and x = 15*2/5 = 6

which was Wednesday's number.  So we get Wed:Fri=6:15=2:5.

icang [17]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Let's try each of the answer choices:

A. Wednesday to Friday

On Wednesday, 6 computers were sold and on Friday, 15 were sold. Then we can write 6 : 15, which simplifies to 2 : 5, which matches what we want. So, A is correct.

B. Monday to Thursday

On Monday, 8 computers were sold and on Thursday, 16 were sold. Then we can write 8 : 16, which simplifies to 1 : 2, which does not match what we want. So, B is incorrect.

C. Tuesday to Friday

On Tuesday, 12 computers were sold and on Friday, 15 were sold. Then we can write 12 : 15, which simplifies to 4 : 5, which also does not match what we want. So, C is incorrect.

D. Thursday to Tuesday

On Thursday, 16 computers were sold and on Tuesday, 12 were sold. Then we can write 16 : 12, which simplifies to 4 : 3, which still does not match what we want. So, D is incorrect.

The answer is thus A.

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What is 403,000,000,000,000 in scientific
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Answer:

(A) 4.03 x 10^14

Step-by-step explanation:

403,000,000,000,000

Scientific notation is of the form

a * 10 ^b

where a is a number from 1 to a number less than 10

Put the decimal in the number

403,000,000,000,000.

We need to move the decimal 14 places to the left to get the number to be between 1 and 10

4.03000000000000  so the b is 14

Since we moved it to the left b is positive

We can drop the extra zeros at the end (after the last nonzero digit)

4.03 *10^14

6 0
3 years ago
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As x heads off to negative infinity (towards the left side), the curve slowly approaches the horizontal line y = 1. It will never actually touch or cross this horizontal line. It simply gets closer and closer. Think of it as an electric fence of sorts.

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The sum of three consecutive odd numbers is 69. What is the biggest number?
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Step-by-step explanation:

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3 years ago
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

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3 years ago
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Answer:

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Step-by-step explanation:

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