You can do this by drawing one line through parallel to PQS to meet RQ at T
Now calculate length of RT:-
cos 70 = RT / 70 giving RT = 23.94m
sin 70 = ST/70 giving ST = 65.78 m
draw a line from S perpendicular to PQ to meet PQ at U.
PU = 110 - 65.78 = 44.22 m
tan 50 = SU / 44.22 giving SU = 52.70 m
TQ = SU = 52.70 m
So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.
Answer is 12.73
Use Pythagorean theory
Split square into two right triangles with diagonal line. To find the diagonal
a^2 + b^2 = c^2
9^2 + 9^2 = c^2
162= c^2
Take square root of both sides
12.73 = c
Since x³ = x^(1/3) you can say that
(x¹⁰)^(1/3) = x^10/3 = x^(3 + 1/3) =
x³ ·∛x
Answer:
262440
Step-by-step explanation:
108/100×243000
Answer:
umm let me look at this one more time then I will answer:)