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Marina86 [1]
3 years ago
7

Solve the system by using a matrix equation.4x-3y=66x-4y=4​

Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

The answer to your question is:

x = -6

y = -10

Step-by-step explanation:

Δ = \left[\begin{array}{ccc}4&-3\\6&-4\end{array}\right] \\

Δ = -16 + 18

Δ = 2

Δx = \left[\begin{array}{ccc}6&-3\\4&-4\\\end{array}\right]

Δx = -24 +12

Δx = -12

Δy = \left[\begin{array}{ccc}4&6\\6&4\\\end{array}\right]

Δy = 16 - 36

Δy = -20

x = -12/2 = -6

y = -20 / 2 = -10

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we have

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Factor the leading coefficient

8(x^2+\frac{13}{8}x) = 6

Complete the square. Remember to balance the equation by adding the same constants to each side.

8(x^2+\frac{13}{8}x) = 6

8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16}  \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2

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therefore

<u>the answer is</u>

(8x-3)*(x+2)




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