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kodGreya [7K]
2 years ago
15

Pls help asap !!!!!!​

Mathematics
1 answer:
Licemer1 [7]2 years ago
3 0

Answer:

The <u>MEDIAN</u>, <u>4.5</u> hours, is the best measure of center, so the <u>IQR</u> is the best measure of variability.

McKennas conclusion <u>IS NOT</u> accurate.  The mode of her data <u>IS</u> 6 hours.  However, <u>MORE</u> than half of the time, she spends <u>LESS</u> than 6 hours riding her horse.  It would be more accurate to say that Mckenna typically rides her horse between <u>2.5</u> and 6 hours.

Step-by-step explanation:

Put the values in order of smallest to largest:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

Median (middle value) = (4 + 5)/2 = 4.5

Lower quartile Q1 = 2.5

Upper quartlie Q3 = 6

IQR = Q3 - Q1 = 3.5

Mode (value that occurs most often) = 6

Mean (average) = sum of values ÷ number of values = 4.7

Range (difference between the highest and lowest values) = 10 - 0 = 10

Median is the best measure of the center since it isn't influenced by extreme values.

IQR is less affected by outliers and extreme values. It gives a consistent measure of variability for skewed data.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The <u>MEDIAN</u>, <u>4.5</u> hours, is the best measure of center, so the <u>IQR</u> is the best measure of variability.

McKennas conclusion <u>IS NOT</u> accurate.  The mode of her data <u>IS</u> 6 hours.  However, <u>MORE</u> than half of the time, she spends <u>LESS</u> than 6 hours riding her horse.  It would be more accurate to say that Mckenna typically rides her horse between <u>2.5</u> and 6 hours.

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