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lukranit [14]
3 years ago
15

Find the difference: 11 - 4.7

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

<u><em>Answer: 6.3 *The answer must be have a decimal point.*</em></u>

Explanation:

First, subtract by the numbers. Subtract it's going to be find the difference between the numbers.

11-4.7=6.3

You can also add by the numbers.

6.3+4.7=11

11-6.3=4.7

Hope this helps!

Thank you!

Have a great day!

Alex_Xolod [135]3 years ago
4 0

Hey there!

Answer = 6.3

Explanation:

All you have to do is subtract.

= 11 - 4.7

= 11 + -4.7

= 6.3

So therefore, that is how you found your answer: 6.3

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andrew-mc [135]

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5 0
3 years ago
Anyone know these two questions??
gogolik [260]

1):  Answer  =====>  Letter Choice, (B),  The rate in which you walked home, The slope is the same, as the Rate of Change, In Distance Divided by the Change in Time  =====>    d    =     4   -1/15t(4) / 1/15t

 

2):   The Equation:  d     =       -1/15t     +     4

The more the Number of Minutes:  Larger the Negative Quantity;  ====>   -1/15t

The Larger the Negative Quantity in Equation:  D value is Smaller:

Therefore your Answer ===>  The Distance from home (d), Decreased with Minute Walked (t)  ====>  So, Letter Choice,  (C)



2):   Towards your home, The slope is Negative, and the Distance (y - value), Decreases, as the Time  (x- Values),  Increases. Notice the Slope is Negative, Because, you are getting closer to home.






Hope that helps!!!!                                           : )

7 0
3 years ago
Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher
Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find <em>t</em>.

A(t)=A_{0}(1/2)^t^/^h

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For A_{0 let's just assume that there are 100 original  atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. <em>h</em> is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

74=100(1/2)^t^/^5^7^3^0

Now, solve. First, divide by 100.

0.74=(0.5)^t^/^5^7^3^0

Take the log of everything

log(0.74)=\frac{t}{5730} log(0.5)

Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the <em>t</em> and get

5730\frac{log(0.74)}{log(0.5)} =t

Use your calculator to solve that giant mess for <em>t </em>and you'll get that <em>t</em> is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0
3 years ago
the coordinates of a line segment are (1,6) and (11, -4). what is the length of the line segment? round your answer to the neare
ddd [48]
The length of the line segment AB where A(x_A;\ y_A) and B(x_B;\ y_B)

|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

We have: A(1;\ 6);\ B(11;-4)

subtitute

|AB|=\sqrt{(1-11)^2+(6-(-4))^2}=\sqrt{(-10)^2+10^2}=\sqrt{100+100}\\\\=\sqrt{100\cdot2}=\sqrt{100}\cdot\sqrt2=10\sqrt2\approx14.1

Answer: b. 14.1
3 0
3 years ago
A triangle has sides measuring 1.5 m, 2 m and 2.5 m. Show that this is a right-angled triangle.​
Nady [450]

Answer:

Yes, this is a right triangle

Step-by-step explanation:

Plug the values into the pythagorean thm.

1.5^2 + 2^2 = 2.5^2

2.25+4=6.25

6.25=6.25

7 0
3 years ago
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