Plug in 7 for x and 24 for v
Answer:
A)
Step-by-step explanation:
lw=A
divide both sides by l
lw÷l=A÷l
w=A÷l
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
If you're asking what the perimeter is:
C 32cm
If you're asking what the length of a side is:
A 8cm
Step-by-step explanation:
Area of a square is calculated by length x width.
And all four sides of a square are equal in length.
Area: 8cm×8cm=64cm2
Perimeter: 8cm + 8cm + 8cm + 8cm= 32cm
Another way to find the length of the sides would be to take the square root of 64. I believe that only works with the area of a square though.
√(64)=8
