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juin [17]
2 years ago
12

Question 1 (Essay Worth 10 points)

Mathematics
1 answer:
Shalnov [3]2 years ago
6 0

✿————✦————✿————✦————✿

The answer is: <u>2(k2−4k)(2c+5)</u>

✿————✦————✿————✦————✿

Step:

* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.

* Factor out the common term 2c+5 by using the distributive property.

* Rewrite the complete factored expression.

✿————✦————✿————✦————✿

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What is the factored form of 6n4 – 24n3 + 18n?
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Answer: Its factored form will be

6n(n-1)(n^2-3n-3)

Step-by-step explanation:

Since we have given that

6n^4-24n^3+18n

So, we need to factor ,

6n(n^3-4n^2+3)

Now,

\text{Let }p(n)=n^3-4n^2+3

Now, by hit and trial method, we put n=1,

p(1)=1^3-4\times1^2+3=1-4+3=1-1=0

n=1\\n-1=0

So, n-1 is also factor of p(n).

Now,

\frac{n^3-4n^2+3}{n-1}=n^2-3n-3

So, its factored form will be

6n(n-1)(n^2-3n-3)

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Answer:

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What did you do? What is this mess but thanks for the points

Step-by-step explanation:

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