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neonofarm [45]
3 years ago
10

I WILL GIVE YOU A COOKIE IF YOU ANSWER THIS QUESTION CORRECTLY!!!

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

2308.4mm^3

Step-by-step explanation:

V=(4/3)πr^3

V = (4/3)π8.2^3

V= (4/3)π x 551.368

V = 2308.39

(2308.4 if rounded to tenths)

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Russell runs 9/10 mike in 5 mins. How many miles does he run in one minute
STALIN [3.7K]

Answer:

0.18 miles per minute.

Step-by-step explanation:

You need to divide 9/10 miles by 5 because 5 minutes/5=1 minute.

9/10/5=0.18 (or 18/100)

6 0
3 years ago
How would I do this plz help
kari74 [83]

Answer:

273 m^2

Step-by-step explanation:

Firstly, you should find the area of the triangle. Remember that the formula for a triangle's area is (Base x Height) ÷ 2

Therefore,

11 x 14 is 154

154/2 = 77 m^2

Then, we find the area of the square which is just Base x Heigh

14 x 14 is 196m^2

And finally, we just add the two

77 + 196 = 273 m^2

The reason it's not m^3 is because we're not dealing with a third dimensional figure.

Btw, ^ means to the power of.

7 0
4 years ago
Solve for d.<br> 85 = 5(d − 68)
Talja [164]

Answer:

Step-by-step explanation:

5(d - 68) = 85

Use distributive property

5*d - 68*5 = 85

5d - 340 = 85

Add 340to both sides

5d = 85 + 340

5d = 425

Divide both side by 5

d = 425/5

d = 85

6 0
3 years ago
Read 2 more answers
A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects
Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have p=10 groups and on each group from j=1,\dots,p=10 we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

And we have this property

SST=SS_{between}+SS_{within}

Solution to the problem

Part a

(i) confidence interval

False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.

(ii) t-test

Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.

(iii) ANOVA

This one is the best method when we want to compare more than 1 group of means.

(iv) Chi square

False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.

Part b

The ANOVA test is more powerful than the t test when we want to compare  group of means.

8 0
4 years ago
Choose the equivalent system of linear equations that will produce the same solution as the one given below.
dmitriy555 [2]
<span>C: 3x + 2y = 6
7x =12


Tell me if this helps, Have a great day!</span>
6 0
4 years ago
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