Answer:1.5 i think
Step-by-step explanation:
2 days to get this apology. its really does suck to not get your question answered in the firs ten min <span />
Answer:
The length of one side is 13 feet.
Step-by-step explanation:
To start, a square is 4 sides that are equal in length. This means that when you have a problem like this, you need to set the equations equal to each other like:

In order to solve a problem like this, with the same variables on different sides, start by subtracting the smaller variable from both sides. In this case, you would be subtracting 2x from both sides, which would leave us with:

After that, you solve it like a normal one-step equation. Add 11 to both sides.
Now, divide both sides by 4 and you will know how much
is worth.

Now that we know how much
is worth, we can plug that into either of the equations given to us. It doesn't matter which since they are equal to each other.

That would give us 13.
primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a
![a=\sqrt[]{hipotenusa^2-cateto^2}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7Bhipotenusa%5E2-cateto%5E2%7D)
![a=\sqrt[]{100^2-85^2}=52.68](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7B100%5E2-85%5E2%7D%3D52.68)
a=52.68 m
teniendo el lado faltante podemos calcular las razones trigonometricas




