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Nana76 [90]
3 years ago
8

GJ bisects ∠FGH and is a perpendicular bisector of FH. What is true of triangle FGH?

Mathematics
2 answers:
professor190 [17]3 years ago
6 0
Referring to the image attached:

this is an isosceles triangle

Elena-2011 [213]3 years ago
4 0

Answer:

It has exactly two congruent sides

Step-by-step explanation:

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9: 1/2e=1/4
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BigorU [14]

9514 1404 393

Answer:

  • arc BC = 60°
  • m∠ADC = 60°
  • m∠AEB = 105°
  • m∠ADP = 45°
  • m∠P = 60°

Step-by-step explanation:

The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...

  CB : BA : AD : DC = 2 : 2 : 3 : 5

The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...

  arc BC = arc BA = 60° . . . . 2 ratio units each

  arc AD = 90° . . . . . . . . . . . . 3 ratio units

  arc DC = 150° . . . . . . . . . . . .5 ratio units

The inscribed angles are half the measure of the intercepted arcs:

  ∠ADC = (1/2) arc AC = 1/2(120°) = 60°

  ∠ADP = 1/2 arc AD = 1/2(90°) = 45°

The angles at E are half the sum of the measures of the intercepted arcs.

  ∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°

Angle P is half the difference of the intercepted arcs.

  ∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°

__

In summary, ...

  arc BC = 60°

  m∠ADC = 60°

  m∠AEB = 105°

  m∠ADP = 45°

  m∠P = 60°

6 0
3 years ago
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