Answer:
Please see attached
Step-by-step explanation:
Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.
Hope this helps.
The answer to your question is 1.6
Answer:
one solution
(second option listed)
Step-by-step explanation:
We can that these two lines, each representing one equation/function, only meet at one specific value.
In a system of equations, we are essentially looking for a solution that works for both equations.
So, if both lines share a point/value (meaning they intersect), that point is a solution to the system of equations.
Because these lines only overlap at one point, this system of equations has one solution.
