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marshall27 [118]
3 years ago
15

Factories:

"xy - 5y + 2x - 10" align="absmiddle" class="latex-formula">
plzz ans​
Mathematics
1 answer:
Ganezh [65]3 years ago
4 0
Xy - 5y + 2x - 10. y ( x - 5 ) + 2 ( x - 5). =. ( y + 2 ) ( x - 5)
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Use the spinner below to find the probability of getting the following number after 1 spin. P(multiple of 3) = (Round to 4 decim
Talja [164]

The value of the probability P(multiple of 3) is 0.3333

<h3>How to determine the probability?</h3>

The spinner that completes the question is added as an attachment

From the attached spinner, we have:

  • Total section = 12
  • Multiples of 3 = 4

The probability is then calculated as:

P(multiple of 3) = Multiples of 3/Total

This gives

P(multiple of 3) = 4/12

Evaluate

P(multiple of 3) = 0.3333

Hence, the value of the probability is 0.3333

Read more about probability at:

brainly.com/question/25870256

#SPJ1

3 0
2 years ago
Hiiii!
fenix001 [56]

Answer:

100,000,000

Step-by-step explanation:

You can just add up the zeros, if that makes sense.

5 0
3 years ago
Read 2 more answers
What is 37.726 rounded to the nearest tenth
pochemuha
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

37.7\fbox26\approx\huge\boxed{37.7}
7 0
3 years ago
Read 2 more answers
Which of the following expressions has a value between 5 and 6.
Airida [17]
So listen to this logic
lets say you have 3 numbers, m,a,x where they are all positivie
m>a>x
therefor
m^2>a>2>x^2
if m and a and x are square roots, therefor we can reverse the square root
confusing sorry

square 5 and 6
5^2=25
6^2=36

the number betwe 25 and 36

that would be 32

answer is √32

goes like this
5^2<32<6^2
sqrt both sides
5<√32<6

answer is √32
8 0
3 years ago
Read 2 more answers
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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