-5^2+9x-9 (need more space to answer)
Let that be

Two vertical asymptotes at -1 and 0

If we simply

- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is

Graph attached
Answer:
325 km
Step-by-step explanation:
Given the scale :
1 : 4 ,000, 000
1cm measure in map = 4000000 on the ground
From the map :
Distance between Leeds and London = 8.125 cm
The actual distance on ground can be calculated thus :
1cm = 4,000,000
8.125cm = x
Cross multiply
x = 32500000 cm
Converting to kilometers :
1 km = 100,000 cm
x = 32500000
Cross multiply
100,000x = 32500000
x = 32500000 / 100000
x = 325
Hence, actual distance between Leeds and London is 325 km
They each get 14 cents,
A quarter = 25c
A nickel = 5c
A dime = 10c
2 pennies = 2c
25 + 5 + 10 + 2 = 42c
42 divided by 3 is 14 cents
So Willie, Donald and Maya get 14 cents each
Answer:
8
Step-by-step explanation:
24 bottles = 16 dollars!
? bottles = 12 dollars
Note:
In these type of Questions, find out any dollars you could get with 1 bottle
or in simple terms, (first find the unit Rate)
<em>24/16 = 1.5</em>
1 bottle = 1.5 dollars
? bottles = 12 Dollars?
12/1.5
= 8
<h2>I hope that helps! </h2><h3>Have a wonderful day! </h3>