All categories

2 years ago

Please answer my question now in two minutes

Mathematics

1 answer:

Tresset [83]2 years ago

3 0

Answer:

given,triangle EFG is congruent to triangle HIJ,THEIR corresponding sides are equal,

so, 10x=x+45

10x_x=45

or,9x=45

therefore , x=5

again,

3y = y+14

or, 3y_y=14

or, y=14/2

therefore the value of y is 7.

so the value of x is 5 and y is 7.

hope its helpful to uh...

You might be interested in

Please help<br><br>numbers 42, 43, 44

Aleks [24]

<h3>Answer:</h3>

42. 29°

43. 3x³ +2x² -3x +10

44. 20a² +68a

<h3>Step-by-step explanation:</h3>

42. The right-angle corner tells you the two marked angles are complementary — they sum to 90°.

(-3x +20)° + (-2x +55)° = 90°

-5x +75 = 90 . . . . . . . . . . collect terms, divide by °

-5x = 15 . . . . . . . . . . . . . . . subtract 75

x = -3 . . . . . divide by the coefficient of x

The angle of interest is (-3x+20)°. Filling in the found value for x, we have ...

(-3·(-3) +20)° = 29° = m∠BDC

___

43. The distributive property is useful for multiplying polynomials.

(x +2)(3x² -4x +5) = x(3x² -4x +5) +2(3x² -4x +5)

= 3x³ -4x² +5x +6x² -8x +10 . . . . . eliminate parentheses

= 3x³ +2x² -3x +10

___

44. Area is the product of length and width, so this becomes a problem in multiplying polynomials.

area = (5a +17)(4a) = 20a² +68a . . . . area in square feet

3 0

3 years ago

Answer please!!!!!!!!!

Veronika [31]

Answer:

B. y = 2 / 3 x + 1

Step-by-step explanation:

Looking at the graph, you can see that the y-intercept is 1, so you can eliminate choices A and D. You are now left between choices B and C. To figure out the slope, you need to do rise and run. From the y-intercept, you rise up 2, and you run right 3. This means that the slope is 2/3.

5 0

3 years ago

Read 2 more answers

How to find out the value of the lettered sides

umka2103 [35]

Step-by-step explanation:

sin 46°= a/12.8

a = sin46° * 12.8 = 9.20

cos59°=b/16.8

b = cos59°*16.8 = 8.65

3 0

3 years ago

Read 2 more answers

Find the complex zeros of <br><img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5

timama [110]

$f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3) - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\$

$\\\implies x =3~~ \text{ or} ~~ x =5 \pm 2i\\\\\text{Hence the complex roots are,}~ 5- 2i ~~ \text{and} ~~5 + 2i$

6 0

2 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

2 years ago