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oksian1 [2.3K]
3 years ago
7

What is the answer for the algebra equation Ab•2b

Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

\huge\bold\purple{      2a•3b          }

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Write the prime factorization for 65,169
posledela

Let's try to find some primes that divide this number.

The number is not divisible by 2, because it is odd.

The number is divisible by 3 though, because the sum of its digits is:

6+5+1+6+9=27=3\cdot 9

So, we can divide the number by 3 and keep going with the factorization:

65169\div 3 = 21723

This number is again divisible by 3, because

2+1+7+2+3 = 15 = 3\cdot 5

We have

21723\div 3 = 7241

This number is no longer divisible by 3. Let's go on looking for primes that divide it: 5 doesn't because the number doesn't end in 0 nor 5. This number is not divisible by 7 or 11 either (just try). It is divisible by 13 though: we have

7241\div 13 = 557

And 557 is prime, so we're done. This means that the prime factorization of 65169 is

3^2\cdot 13 \cdot 557

8 0
3 years ago
Joe has 17 coins, nickels and dimes, that total up to $1.25. How many nickels does he have?
kifflom [539]

Answer:

9 nickels

Step-by-step explanation:

He has 17 coins.

$1.25 is 12 dimes and 1 nickel. But that is only 13 coins.

$1.25 can only be 17 coins if there were 9 nickels and 8 dimes.


6 0
4 years ago
The numbers 81, 45,27 are multiplies of
malfutka [58]
They are multiplis of 9
4 0
3 years ago
Read 2 more answers
Unit 17- calculations
OLEGan [10]

What exactly is your question?

4 0
3 years ago
Read 2 more answers
PLEASE PLEASE HELP
marta [7]

Answer:

Approximately 3 grams left.

Step-by-step explanation:

We will utilize the standard form of an exponential function, given by:

f(t)=a(r)^t

In the case of half-life, our rate <em>r</em> will be 1/2. This is because 1/2 or 50% will be left after <em>t </em>half-lives.

Our initial amount <em>a </em>is 185 grams.

So, by substitution, we have:

\displaystyle f(t)=185\big(\frac{1}{2}\big)^t

Where <em>f(t)</em> denotes the amount of grams left after <em>t</em> half-lives.

We want to find the amount left after 6 half-lives. Therefore, <em>t </em>= 6. Then using our function, we acquire:

\displaystyle f(6)=185\big(\frac{1}{2}\big)^6

Evaluate:

\displaystyle f(6)=185\big(\frac{1}{64}\big)\approx2.89\approx 3

So, after six half-lives, there will be approximately 3 grams left.

3 0
3 years ago
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