Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.
<h3>What is the mechanism of amobarbital?</h3>
Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.
Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.
So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.
Learn more about Amobarbital here: brainly.com/question/7237163
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Electrons because the amount of valence electrons determines the bonds it can form and often times during a chemical bond or the forming of a compound an element will lose some of its electrons.
Answer:
3 element i.e carbon (C), hydrogen (H) and oxygen.
Explanation:
The following data were obtained from the question:
Subtance >>>>>>>> Chemical Formula
Glucose >>>>>>>>> C₆H₁₂O₆
Methane >>>>>>>> CH₄
Ethanol >>>>>>>>> C₂H₅OH
Hydrogen peroxide >> H₂O₂
From the above table, we can see that ethanol (C₂H₅OH) contains carbon (C), hydrogen (H) and oxygen
Therefore, the total number of elements present in ethanol, C₂H₅OH is 3.
2.
On the left side of the equation, there are two Li and two NO3. Therefore, the balanced equation on the right should be 2Li(NO3)
Answer:
C. Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.
Explanation:
- Atoms of elements gain or lose electron(s) to obey the octet rule by forming cations or anions.
- Atoms with 1 to 3 valence electrons lose electrons to form cations in order to attain a stable configuration.
- Atoms with 5 to 7 valence electrons gain electron(s) to form anions in order to attain stable configuration.
- However, atoms with 8 valence electrons do not require to gain or lose electrons since they an octet configuration.
- Atoms of metallic elements such as those in group 1 and 2 lose electron(s) to form cations while atoms of non-metallic elements such as halogens require to gain electron(s) to form anions so as to obey the octet rule.
