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Sedaia [141]
3 years ago
14

How are the graphs of the sine function and the cosine function different?

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
3 0
They are different by a phase shift of pi/2
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3 years ago
A dependent variable is
Ivanshal [37]

Answer:

a variable (often denoted by y ) whose value depends on that of another.

Explanation:

a variable (often denoted by y ) whose value depends on that of another.

7 0
3 years ago
2.0g divided by 34.0 g times 100% equals what?
Lubov Fominskaja [6]

Answer: \frac{1}{17}

Explanation: \frac{2}{34}\cdot \:100\%\:=\frac{1}{17}

I tried my best, I hope this helps!

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3 years ago
The cell of your body need energy to carry out life function. Which of the following body responses is a sign that your cells ne
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3 years ago
What is the molarity (M) of chloride ions in a solution prepared by mixing 155 ml of 0.276 M calcium chloride with 384 ml of 0.4
sesenic [268]

Answer: The concentration of Cl^- ions in the resulting solution is 1.16 M.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the CaCl_2

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the AlCl_3

We are given:

n_1=2\\M_1=0.276M\\V_1=155mL\\n_2=3\\M_2=0.471M\\V_2=384mL  

Putting all the values in above equation, we get

M=\frac{(2\times 0.276\times 155)+(3\times 0.471\times 384)}{155+384}\\\\M=1.16M

The concentration of Cl^- ions in the resulting solution will be same as the molarity of solution which is 1.16 M.

Hence, the concentration of Cl^- ions in the resulting solution is 1.16 M.

6 0
3 years ago
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