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zlopas [31]
3 years ago
11

Rank these elements according to FIRST ionization energy, from highest to lowest:

Chemistry
2 answers:
Rzqust [24]3 years ago
3 0
The trend of ionization energy in the periodic table is decreasing from right to left and from top to bottom. In this case, we are given with elements <span>K, Ca, Ge, Se, Br, Kr and see the periodic table to check the trend. The answer from highest to lowest Kr, Br, Se, Ge, Ca, and K</span>
Zina [86]3 years ago
3 0

The order of the first ionization energy of the given elements from highest to lowest is \boxed{{\mathbf{Kr > Br > Se > Ge > Ca > K}}}

Further Explanation:

The energy that is needed to remove the most loosely bound valence electrons from the isolated neutral atom of the gas is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.

Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as {\text{I}}{{\text{E}}_1} . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy \left( {{\text{I}}{{\text{E}}_2}} \right) and so on.

Potassium, calcium, germanium, selenium, bromine, and krypton belong to the same period of the periodic table.

Along a period, the atomic number increases but the number of shells remains the same while moving from left to right.

The number of protons, as well as the electrons, increases with the increase in the atomic number but the extra electrons are added in the same shell. Due to the high positive nuclear charge, the effective nuclear charge also increases. This results in an increase in the first ionization energy. So krypton will have the highest first ionization energy, followed by bromine, selenium, germanium, calcium, and potassium will have the lowest ionization energy.

Learn more:  

1. Why is {\text{6 - decene}}  not possible: brainly.com/question/2095052

2. The gold foil experiment: brainly.com/question/1859083

Answer details:  

Grade: Senior School  

Subject: Chemistry  

Chapter: Periodic classification of elements

Keywords: first ionization energy , K, Ca, Ge, Se, Br, Kr, protons, electrons, atomic number, isolated, neutral, atom, nuclear charge.

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Methylpropane (complete and condensed structural formulas)
Tcecarenko [31]

Answer:

Here's what I get  

Explanation:

1. Complete structural formula

Methylpropane consists of a chain of three carbons with another carbon atom attached to the middle carbon. Enough H atoms are added to give each C atom a total of four bonds.

The complete structural formula is shown below (There is a C atom at each intersection).

2. Condensed structural formula

A condensed structural formula is designed to be typed on one line.

The molecule has three CH₃ groups attached to a single carbon atom, so the condensed structural formula is  

(CH₃)₃CH

The formula is also often written CH₃CH(CH₃)CH₃ and as (CH₃)₂CHCH₃.

5 0
3 years ago
What structure holds the sister chromatids to the spindle fibers?
olganol [36]
The answer is <span>a. kinetochore.

A kinetochore is a protein structure that holds the </span><span>sister chromatids to the spindle fibers. It is the place on chromatids where the spindle fibers bind during the cell division. As the result, sister chromatids are pulled apart to the opposite ends of the cell.</span>
8 0
3 years ago
Consider the reaction ch3oh(l)→ch4(g)+1/2o2(g). part a calculate δrh∘298.
Vsevolod [243]
To determine the standard heat of reaction, ΔHrxn°, let's apply the Hess' Law.

ΔHrxn° = ∑(ν×ΔHf° of products) - ∑(ν×ΔHf° of reactants)
where
ν si the stoichiometric coefficient of the substances in the reaction
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The ΔHf° for the substances are the following:
CH₃OH(l) = -238.4 kJ/mol
CH₄(g) = -74.7 kJ/mol
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8 0
2 years ago
Read 2 more answers
3. Determine the pH of each of the following solutions. (Hint: See Sample Problem B.) a. 1.0 x 10-2 M HCI c. 1.0 x 10-MHI b. 1.0
densk [106]

Answer:

a. pH = 2 b. pH = 3 c. pH = 1 d. Unanswerable

Explanation:

pH = -log[H+] OR pH = -log{H3O+]

                    and inversely

pOH = -log[OH-]

1. Determine what substance you are working with, (acid/base)

2. Determine whether or not that acid or base is strong or weak.

a. 1.0 x 10^-2M HCl

HCl is a strong acid, therefore it will dissociate completely into H+ and Cl- with all ions going to the H+, therefore, the concentration of HCl and concentration of H+ are going to be equal, meaning we simply take the negative logarithm of the concentration of HCl and that would equal pH

pH = -log[H+]

pH = -log(1.0x10^-2)

pH = 2

b. 1.0 x 10^-3M HNO3

HNO3 like part a, is a strong acid, therefore it would simply require you to take the negative logarithm of the concentration of the compound itself, to find its pH.

pH = -log[H+]

pH = -log(1.0 x 10^-3)

pH = 3

c. 1.0 x 10^-1M HI

Like the previous parts, HI is a strong acid

pH = -log[H+]

pH = -log(0.10)

pH = 1

d. HB isn't an element, nor is it a compound so that would be unanswerable.

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3 years ago
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almond37 [142]
I do not understand your question, what is the question, name what??
5 0
3 years ago
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