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zlopas [31]
4 years ago
11

Rank these elements according to FIRST ionization energy, from highest to lowest:

Chemistry
2 answers:
Rzqust [24]4 years ago
3 0
The trend of ionization energy in the periodic table is decreasing from right to left and from top to bottom. In this case, we are given with elements <span>K, Ca, Ge, Se, Br, Kr and see the periodic table to check the trend. The answer from highest to lowest Kr, Br, Se, Ge, Ca, and K</span>
Zina [86]4 years ago
3 0

The order of the first ionization energy of the given elements from highest to lowest is \boxed{{\mathbf{Kr > Br > Se > Ge > Ca > K}}}

Further Explanation:

The energy that is needed to remove the most loosely bound valence electrons from the isolated neutral atom of the gas is known as the ionization energy. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.

Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as {\text{I}}{{\text{E}}_1} . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy \left( {{\text{I}}{{\text{E}}_2}} \right) and so on.

Potassium, calcium, germanium, selenium, bromine, and krypton belong to the same period of the periodic table.

Along a period, the atomic number increases but the number of shells remains the same while moving from left to right.

The number of protons, as well as the electrons, increases with the increase in the atomic number but the extra electrons are added in the same shell. Due to the high positive nuclear charge, the effective nuclear charge also increases. This results in an increase in the first ionization energy. So krypton will have the highest first ionization energy, followed by bromine, selenium, germanium, calcium, and potassium will have the lowest ionization energy.

Learn more:  

1. Why is {\text{6 - decene}}  not possible: brainly.com/question/2095052

2. The gold foil experiment: brainly.com/question/1859083

Answer details:  

Grade: Senior School  

Subject: Chemistry  

Chapter: Periodic classification of elements

Keywords: first ionization energy , K, Ca, Ge, Se, Br, Kr, protons, electrons, atomic number, isolated, neutral, atom, nuclear charge.

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What volume does 1.70 ×10–3 mol of chlorine gas occupy if its temperature is 20.2 °C and its pressure is 795 mm Hg?
Cerrena [4.2K]

Explanation:

The given data is as follows.

     No. of moles = 1.70 \times 10^{-3},           V = ?

     T = 20.2 + 273 K = 293.2 K,             P = \frac{795 mm Hg}{760.0 mm Hg/atm} = 1.046 atm,                      R = 0.0821 L atm K^{-1}mol ^{-1}

Calculate the volume using ideal gas equation as follows.

                                    P V = n R T

    1.046 atm \times V = 1.70 \times 10^{-3} \times 0.0821 L atm K^{-1}mol ^{-1} \times 293.2 K

                                  V = \frac{1.70 \times 10^{-3} \times 0.0821 L atm K^{-1}mol ^{-1} \times 293.2 K}{1.046 atm}

                                   = \frac{40.921 L atm}{1.046 atm}

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Thus, we can conclude that volume of the gas is 39.122 \times 10^{-3} L.


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3 years ago
What kind of acid is chlorous acid?<br><br>A Monoprotic acid<br>B Diprotic acid<br>C Triprotic acid​
tangare [24]

Answer:

It might be B

Explanation:

because its HClO2

7 0
4 years ago
Read 2 more answers
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