2x+4y=0
substitute y with 0
2x+4(0)=0
solve the equation
2x+0=0
2x=0
divide by 2 on both sides
x=0
4x+8y=7
substitute y with 0
4x+8(0)=7
solve the equation
4x+0=7
4x=7
divide by 4 on both sides
x=7/4 or x=1 3/4 or x=1.75
3x-7y=-29
2x+2y=6
solve the bottom equation
3x-7y=-29
x=3-y
substitute for x
3(3-y)-7y=-29
solve the equation
y=19/5
now substitute for y
x=3-
solve for x
x=-4/5
the possible solution of the system is the ordered pair
(x,y)=(
)
5.972 × 10<span>21.
Hope this helps.</span>
Answer:
The three digit number = 951
Step-by-step explanation:
Let suppose the numbers are:
= abc
According to given condition:
a+ b + c = 15 -------------eq1
Also, given the difference between the first two digit = the difference between the last two digits:
==> l a-b l = l b-cl
==> (a-b) = (b-c)
==> (a+c) = 2b
Now we will substitue in eq1
==> a+ b + c = 15
==> 2b + b = 15
==> 3b = 15
Dividing both sides by 3 we get:
b =5
a + c = 2b
a+ c = 10
a = 10 -c ..........(2)
We know that"
(a-b) = (b-c)
==> a > b+c
==> a > 5 + c
==> 10 -c > 5 +c
==>5 > 2c
==> 2.5 > c
As c is an odd number so c will be equal to 1
c = 1
a = 10 -1
a = 9
The three digit number = 951
The hundred digit is greater than the sum of the tens and ones digits
i hope it will help you!
Answer:
7/12=0.583333333333
Step-by-step explanation:
