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2 years ago

What is the surface area of the cylinder with height 8 mi and radius 6 mi? Round your answer to the nearest thousandth.

Mathematics

2 answers:

diamong [38]2 years ago

4 0

Answer: the real answer is 527.788 the top answer is wrong I did it and it said it was wrong

Step-by-step explanation:

maksim [4K]2 years ago

3 0

Answer:ANSWER would either be 120π or about 376.8

Step-by-step explanation:

A=2πrh+2πr2

A=2π*6*8+2π*6*2

A=96π+24π

A= 120π

A≈376.8

ANSWER would either be 120π or about 376.8

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A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year

Roman55 [17]

Answer:

The required equation is $y = 18(1.15)^x$ .

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

$y = 18(1.15)^x$

Now verify this by substituting x=1 in above equation.

$y = 18(1.15)^1=20.7$

Which is true.

Hence, the required equation is $y = 18(1.15)^x$ .

7 0

3 years ago

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9. Draw the number line graph of 0.4.

Evgesh-ka [11]

The number line graph of 0.4 is here.

4 0

3 years ago

Fred solved the equation 8(3x – 7) = -6(x + 7) + 4 as shown.

OleMash [197]

Answer: He added 4 to a negative 42 and said it was 46 but its supposed to simplify to -38. X=3/5

3 0

2 years ago

Need help wasn't there for a lesson

77julia77 [94]

These are linear equations, so there is x and y. On number one the first thing they plotted was (3,8) so in a function table the 3 would be on the left side and the 8 would be on the right side. I’ll leave you with the rule of the first one, if the rule is times 2 plus to the how would you put it in a function table.

The first thing that you would put into the function table on the first question would be as I said earlier 3 and then 8. The rule is the rate. Using a function table will be very helpful (That’s why I keep mentioning one). Let me know if this helps.

6 0

3 years ago

In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport. in the same district, 19 of 67

Mashcka [7]

Answer:

Standard Error of the difference = 0.0695

Step-by-step explanation:

Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

$\implies P_1=\frac{16}{85}\\\\n_1=85$

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

$\implies P_1=\frac{19}{67}\\\\n_2=67$

Now, finding the standard error of the difference :

$\text{Standard Error = }\sqrt{\frac{P_1(1-P_1)}{n_1}+\frac{P_2(1-P_2)}{n_2}}\\\\\implies \text{Standard Error = }\sqrt{\frac{\frac{16}{85}(1-\frac{16}{85})}{85}+\frac{\frac{19}{67}(1-\frac{19}{67})}{67}}\\\\\implies\text{Standard Error = }0.0695$

Hence, Standard Error of the difference = 0.0695

6 0

3 years ago

Read 2 more answers