With a SSS you’ll only see the little tick marks but on a SAS you’ll see a tick, angle indication, then another tick
(−m)(n)p(3m−5n+7p)
=((−m)(n)p)(3m+−5n+7p)
=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)
=−3m^2np+5mn^2p−7mnp^2
discriminant= b^2-4ac= (-2)^2-4(4)(9)= -140<0
since discriminant <0, graph is always positive, x has no real roots
Answer;
S
=
2
(
(
−
y
+
11
2
,
y
−
7
2
)
2
+
4
−
3
(
−
y
+
11
2
,
y
−
7
2
)
)
y
x
=
−
y
2
+
11
2
x
=
y
2
−
7
2
Step-by-step explanation:
divide each term by y then simplify
It is important to understand the meaning of orthocenter in respect to a triangle first. Ii is actually the intersection of all the altitudes within a triangle. The altitudes can be drawn from an angle to the opposite side but the line should create a right angle with the side of the triangle. In case of obtuse triangle, the three lines would meet outside the triangle. I hope the answer helps.
