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Luda [366]
3 years ago
14

Find the zeros for (x+7) (x+5)+0

Mathematics
1 answer:
JulijaS [17]3 years ago
3 0

Steps to solve for the zero:

(x + 7)(x + 5) = 0

~Set both factors to equal zero

x + 7 = 0

x + 5 = 0

~Solve for x in [ x + 7 = 0 ]

x + 7 = 0

x + 7 - 7 = 0 - 7

x = -7

~Solve for x in [ x + 5 = 0 ]

x + 5 = 0

x + 5 - 5 = 0 - 5

x = -5

Therefore, the solutions are x = -7 and x = -5

Best of Luck!

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\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
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3 years ago
What’s the opposite of —10
Nezavi [6.7K]

10 because it is teh number but with the opposite sign opposite of a posiive is a negative


6 0
3 years ago
Read 2 more answers
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