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4 years ago

Solve the equation below for x. -1 2(3x - 4) = 11

2 answers:

7 0

If the -1 is not included, then your answer is 3.17.

2(3x-4)=11

3x2=6 and -4x2= -8

6x-8=11

+8 +8

6x=19

/6 /6

X= 3.17

vovangra [49]4 years ago

3 0

If the -1 not included, then your answer is 3.17.

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What is the solution to the linear equation below? 6 + y = 37

slavikrds [6]

Y=31----------------------------------------------------------------

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4 years ago

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125 cm to 87.4 cm percent of change

netineya [11]

Answer:

% Change = (87.5 - 125) / 125 * 100%

= -37.5 / 125 * 100%

= -0.3 * 100%

= -30 %

The percent change is -30 % or 30% decrease.

4 0

3 years ago

Solve for x in the equation x2 +11x+121/4=125/4

aksik [14]

Answer:

x= −11 2 + 5 2 √5 or x= −11 2 + −5 2 5

Step-by-step explanation:

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3 years ago

Write an exponential function whose graph contains the points (1, 6) and (0, 2).

12345 [234]

Answer:

y = 2 $(3)^{x}$

Step-by-step explanation:

The exponential function is of the form

y = a $(b)^{x}$

To find a and b substitute the given points into the equation

Using (0, 2), then

2 = a $(b)^{0}$ ⇒ a = 2

Using (1, 6), then

6 = 2 $(b)^{1}$ ⇒ b = 3

Equation is y = 2 $(3)^{x}$

6 0

3 years ago

A. Find the common factors of 12 and 20.

Alchen [17]

Answer:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

Step-by-step explanation:

a.) To find the common factors of 12 and 20:

First of all, let us find the factors of 12 and 20

12 = 2 $\times$ 2 $\times$ 3

20 = 2 $\times$ 2 $\times$ 5

The common factors are underlined above i.e. 2, 2.

2. The highest common factor between 12 and 20 is 2 $\times$ 2 = 4

-------------------------------------------

Workbooks are in packs of 25

Textbooks are in pack of 15

The school needs exactly same number of workbooks and textbooks.

And we have to find such least number.

This least number can simply be calculated by finding the LCM (Least Common Multiple).

LCM of two numbers p and q is the minimum number which is completely divisible by both the numbers p and q.

Let us find LCM of 25 and 15 using factorization method:

15 = 3 $\times$ 5

25 = 5 $\times$ 5

The common part is considered only once:

So LCM = 3 $\times$ 5 $\times$ 5 = 75

Hence, number of packs of workbooks to be bought = $\frac{75}{25} = 3$

number of packs of textbooks to be bought = $\frac{75}{15} = 5$

So, the answer are:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

8 0

4 years ago