You would use the equation
F+V=E+2
Answer:
2. Number of workshops attended.
Step-by-step explanation:
The variable of interest for predicting the final exam score and doing regression analysis is workshop attendance. Therefore, the response variable should be the number of workshops attended by each student.
This also agrees with what the college tutoring center staff are considering, which forms the research question: "should the center increase the number of math workshops they offer to help students improve their performance in math classes?"
2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
I will create a set of arbitrary constants (x1,y1) (x2,y2)
slope = y2-y1/x2-x1
y = (y2-y1/x2-x1)x + b
y2 = (y2-y1/x2-x1)x2 + b
b = y2 - (y2-y1/x2-x1)x2
y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]
Choose any points and just
Plug the values and you have a linear function.
NOT SURE IF THAT'S WHAT THE QUESTION WANTS.
We can use the arc length formula to solve this.
Arc length = 
Given arc length is 7 and radius is 5, we can plug in the values and solve for q.

ANSWER:
We can use the equation
to find the value of q. And, the value of q is 80.21°.