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2 years ago

janice correctly answered 21 of the 24 questions. what percent of the questions did she answer correctly?

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

3 0

She got 87.5 percent. you find the answer by setting up a proportion

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Find the exact area of the shaded region. A. 16π−8 cm² B. 42.3 cm² C. 92.5 cm² D. 84.6 cm2

Anika [276]

Answer:

A = (16π - 8) cm^2

Step-by-step explanation:

The shaded area is trhe area of the circle minus rthe area of the truiangle,.

A = πr^2 - bh/2

A = π(4 cm)^2 - (4 cm)(4 cm)/2

A = 16π cm^2 - 8 cm^2

A = (16π - 8) cm^2

5 0

3 years ago

8m^3 - 28m^2 + 6m - 21. You solve by factoring by grouping!!! quick please

Leya [2.2K]

Answer:

$(2m - 7)(4 {m}^{2} + 3)$

Step-by-step explanation:

$8m^3 - 28m^2 + 6m - 21 \\ = 4 {m}^{2} (2 {m} - 7) + 3(2m - 7) \\ = (2m - 7)(4 {m}^{2} + 3)$

4 0

2 years ago

The price of jeans was reduced $6 per week for 7 weeks. By how much did the price of the jeans change over the 7 weeks?

Nataliya [291]

The price changed by $42 over the course of seven weeks

3 0

2 years ago

Read 2 more answers

The competitive advantage of small American factories such as Tolerance Contract Manufacturing lies in their ability to produce

Tom [10]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

$H_0: \sigma^{2} \leq 0.0008\\\\H_a: \sigma^{2} > 0.0008$

The testing states value is:

$\to x^2=\frac{(n-1)s^2}{\sigma^2}=32.6250$

therefor the $\rho - \ value = 0.2931$

Through out the above equation its values Doesn't rejects the H_0 value, and its sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.

5 0

2 years ago

Select the simplification that accurately explains the following statement.

lutik1710 [3]

Answer:

Option (b) is correct.

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2$