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3241004551 [841]
3 years ago
6

Need help with 10 and 11 can’t figure it out

Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0
Wish I could help on so sorry
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Find each absolute value<br><br>| 4+2i |<br><br>| 5-i |<br><br>| -3i |
galina1969 [7]

How to get answer for number 1: | 4+2i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}

How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

Number 3 how to get answer: | -3i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

4 0
3 years ago
Read 2 more answers
The sum of 5.9 and -7.2 is <br>positive <br>zero <br>negative​
Thepotemich [5.8K]

Answer:

Negative

Step-by-step explanation:

It would be -1.3. Because you know? You add?

4 0
3 years ago
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a top athlete sprinting has a power of 1700W the average person running has a power of 1000 W how powerful do u think you are? w
maks197457 [2]
I really dont understand what the W means... But i can definately tell you this: I am a former rythmic gymnast who trained for 5 years, and in gym, i am always first place. True facts
5 0
3 years ago
2(a³+b²+11)+1(3+a³+b+11)
Ann [662]

Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36

Therefore, the simplified form is 3a^3+2b^2+b+36

8 0
4 years ago
How do you know the opposite of a nonzero integer?
Oksi-84 [34.3K]

The opposite of a nonzero integer is the inverse of it. So to get the opposite, change the sign.

For example:

What's the opposite of 3?

-3.

I hope that I explained well :)

3 0
3 years ago
Read 2 more answers
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