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iren [92.7K]
4 years ago
9

PLSSSSS help me!! It's a math question, and im not so sure how to solve this.

Mathematics
1 answer:
djverab [1.8K]4 years ago
6 0

Answer:

Marcus needs to buy at least twice as many pounds of apples as pounds of bananas

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Let f(x)= 3x-2 and g= {(0,2), (1,4), (-2,3), (-1,2)} then evaluate (3f+g)(0)
SOVA2 [1]

Answer:

<h2>-4</h2>

Step-by-step explanation:

(3f+g)(0)=3f(0)+g(0)\\\\f(x)=3x-2\\f(0)-\text{put}\ x=0\\f(0)=3(0)-2=0-2=-2\\3f(0)=3(-2)=-6\\\\g(x):\{\bold{(0,\ 2)},\ (1,\ 4),\ (-2,\ 3),\ (-1,\ 2)\}\to g(0)=2\\\\(3f+g)(0)=-6+2=-4

4 0
3 years ago
Marcelo has 6 red marbles in his marble collection. The red marbles make up 12% of all the marbles. Please show your work and th
mixas84 [53]

Answer:

the answer is 50

Step-by-step explanation:

12                6              600        600

---------  *   ---------   =    ------      ------- =    600/12=50
600              x               600        12

6 0
2 years ago
You pay 12,000 dollars in a rent each year, how much money do you pay each month?
erica [24]

Answer:

1000

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Challenge A family wants to rent a car to go on vacation. Company A charges $75.50 and14¢ per mile. Company B charges $30.50 and
sergiy2304 [10]

Company A charges $75.50 and 14¢ per mile, then for x miles, Company A charges 75.5 + 0.14x dollars

Company B charges $30.50 and 9¢ per mile, then for x miles, Company B charges 30.5 + 0.09x dollars

Subtracting the second equation to the first one,

75.5 + 0.14x

-

30.5 + 0.09x

----------------------

45 + 0.05x

For x miles, Company A charges 45 + 0.05x dollars more than Company B.

6 0
1 year ago
I need math help. If youre solving a geometric sequence, the equation needed is An=A1Rn-1. If A1= 5 and R= -2. My question was "
CaHeK987 [17]

Answer:

Step-by-step explanation:

an = a1 * r^(n - 1)

a1 = first term = 5

r = -2

n = nth term of the sequence

so it starts with 5

second term is :

an = a1 * r^(n - 1)......for second term

a2 = 5 * -2^(2 - 1) =

a2 = 5 * -2^1

a2 = 5 * -2

a2 = -10

an = a1 * r^(n - 1)....looking for a3

a3 = 5 * -2^(3 - 1)

a3 = 5 * -2^2

a3 = 5 * 4

a3 = 20

an = a1 * r^(n - 1)....looking for a4

a4 = 5 * -2^(4 - 1)

a4 = 5 * -2^3

a4 = 5 * -8

a4 = - 40

an = a1 * r^(n - 1)...looking for a5

a5 = 5 * -2^(5 - 1)

a5 = 5 * -2^4

a5 = 5 * 16

a5 = 80

an = a1 * r^(n-1)...looking for a6

a6 = 5 * -2^(6 - 1)

a6 = 5 * -2^5

a6 = 5 * -32

a6 = -160

4 0
4 years ago
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