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3 years ago

What is the product of 2x- 1 and x+4

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

$(2x - 1) \times (x + 4)$
$3 {x}^{2} + 8x - x - 4$
$= 3 {x}^{2} + 7x - 4$

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Muffins cost $3.00 per dozen.

GenaCL600 [577]

Answer:

I agree with both of them

Step-by-step explanation:

A dozen is 12 muffins. Therefore, you pay $3.00 for 12 muffins.

We know that you pay $3.00 for 12 muffins we need to find out how much EACH muffin cost. For that we need to divide $3.00 by 12 which is 0.25.

Now we need to know how much it will cost us for 16 muffins. We use our equation 16*0.25 which is 4. Elena said she will pay 4 so she is right.

Andre said he will buy 8 muffins so we use our equation again 8*0.25 which is 2. He said he will pay 2 so he is right.

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3 years ago

What is the simpler form of (2x-6)^2

KatRina [158]

(2x - 6)^2 = (2x - 6)(2x - 6) = 4x^2 - 12x - 12x + 36 = 4x^2 - 24x + 36

6 0

3 years ago

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Work out (5.32 x 10^-7): (2.5 x 10^-5)<br>Give your answer in standard form

Mrrafil [7]

Answer:

1.33×10^-6

Step-by-step explanation:

5.32 x 10^-7= 5.32×10^(-5-2)= 5.32×10^-2×10^(-5)

=0.0532×10^-5

(0.0532×10^-5) (2.5 x 10^-5)

0.0532×2.5 × 10^-5

0.133×10^-5= 1.33×10^-1 ×10^-5

1.33×10^-6

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2 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

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3 years ago

Solve to following inequality:<br> 2.40 + 2.20x < 9<br> Many thanks<br> <3

Alexxandr [17]

Answer:

4.60<9

Step-by-step explanation:

5 0

3 years ago

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